The cable holding a 2125 kg elevator has a maximum strength of 21,750 N. What is the maximum upward acceleration the cable can give the elevator without breaking

Work done  will be 270 J

What is work energy theorem?

The work-energy theorem states that the net work done by the forces on an object equals the change in its kinetic energy.

according to work force theorem

Work done = Force x direction = FD Cosθ

Even if the force is applied to the opposite direction, the box will move in the direction of East. Firstly it was already 6m towards East and after applying force, the box moves further 3m towards same direction i.e East.

                 = 30 N x (9) cos 0⁰

                 = cos 0⁰ is 1

                 = 270 J

270 J work is done by the force.

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Answer:

slow down your reaction time

Explanation:

because alcohol makes nerve cells in the brain less excited and basically slows them down.

Answer:

F = 800N

the magnitude of the average force exerted on the wall by the ball is 800N

Explanation:

Applying the impulse-momentum equation;

Impulse = change in momentum

Ft = m∆v

F = (m∆v)/t

Where;

F = force

t = time

m = mass

∆v = v2 - v1 = change in velocity

Given;

m = 0.80 kg

t = 0.050 s

The ball strikes the wall horizontally with a speed of 25 m/s, and it bounces back with this same speed.

v2 = 25 m/s

v1 = -25 m/s

∆v = v2 - v1 = 25 - (-25) m/s = 25 +25 = 50 m/s

Substituting the values;

F = (m∆v)/t

F = (0.80×50)/0.05

F = 800N

the magnitude of the average force exerted on the wall by the ball is 800N

Answer:

16

Explanation:

Since frequency in a stretched string f = (n/2L)√T/μ and n, L and μ are constant, f ∝ √T  where T = tension in string

Now f₂/f₁ = √T₂/√T₁

Since f₁ = f (frequency at tension T₁) and f₂ = 4f (since its frequency increases by 2 octaves to 4f at tension T₂).

So,

f₂/f₁ = √T₂/√T₁

4f/f = √T₂/√T₁

√T₂/√T₁ = 4

squaring both sides, we have

(√T₂/√T₁)² = 4²

T₂/T₁ = 16

T₂ = 16T₁

So, the tension would have to increase by a factor of 16

Answer:

3 N.

Explanation:

If you want to know how much two charges push or pull each other, you can use Coulomb's law. It says that the force F depends on how big the charges are (Q and q) and how far apart they are (r). The bigger the charges and the closer they are, the stronger the force. The smaller the charges and the farther they are, the weaker the force. The exact formula is:

F = k | Q q | / r 2

where k is a number that makes everything work out right. It's about 8.99 × 10 9 N ⋅ m 2 / C 2 .

Now let's say you have two charges that are a certain distance r 0 apart and they have a force F 0 between them. What happens if you move them twice as far apart? The new distance is 2 r 0 and the new force is F 1 . How do F 1 and F 0 compare? Well, you can use Coulomb's law again and divide them:

F 1 / F 0 = (k | Q q | / (2 r 0 ) 2 ) / (k | Q q | / r 0 2 )

If you simplify this, you get:

F 1 / F 0 = (1/2) 2

F 1 / F 0 = 1/4

This means that the new force is only one-fourth of the old force. So if the old force was 12 N, then the new force is:

F 1 = F 0 /4

F 1 = (12 N) /4

F 1 = 3 N

So moving the charges twice as far apart makes the force four times weaker. It goes from 12 N to 3 N.

At the critical temperatures of the substance, the substance can't lose any more thermal energy. Hence, option B is correct.

At the critical temperature, the properties of the liquid and gas phases become difficult to differentiate, and the substance exhibits particular type of behavior such as infinite compressibility and a lack of surface tension.

Additionally, at the critical temperature, the substance reaches its maximum vapor pressure, and any further increase in temperature and pressure will not cause it to change its state but only its density and hence, it cannot lose any more thermal energy from itself.

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The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.

To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.

The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.

Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).

To calculate the area, we can break it down into two separate integrals:

1. The area above the x-axis (forward motion):

Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:

Area1 = velocity * time = 20 m/s * 4 s = 80 m

2. The area below the x-axis (backward motion):

The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:

Area2 = velocity * time = -10 m/s * 1 s = -10 m

To find the total distance traveled, we add the absolute values of the areas:

Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m

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If a radio station broadcasts at 9.23 x 10⁷Hz and the velocity of the waves is 3  x 10⁸m/s, the wavelength of these waves is 3.25m.

According to the question,

Frequency of the FM radio = 9.23 x 10⁷Hz

Velocity of the waves = 3  x 10⁸m/s

The wavelength of the wave =?

To find the wavelength of the wave, we conclude the velocity equation;

Velocity = frequency x wavelength.

Since to find unknown is the wavelength, we have to solve for it:

       3  x 10⁸  = 9.23 x 10⁷ x wavelength

      wavelength =    3  x 10⁸/ 9.23 x 10⁷

      wavelength = 3.25m

Therefore, the wavelength of these waves is 3.25m.

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Given the mass of an alien planet,

and the mass of the asteroid is

The asteroid has velocity v1 = 1 m/s when it is at a distance,

We have to find the radius,r, when it hits the surface with velocity v0 = 4982 m/s

In order to find the radius, we have to use the energy formula at two different distances,

one at radius r1 and the other at the radius r.

There are 2 types of energy, one is kinetic energy due to the motion of the asteroid and the other one is gravitational potential energy due to the alien planet.

So, total energy at distance, r1 is given by

Here, G = 6.67 x 10^-11 m^3/Kg s^2 which is the universal gravitational constant.

Also, the total energy at the radius, r is given by

According to the conservation of energy, equations (1) and (2) are equal

Rewriting the equation for radius,

Substituting the values in the above equation, we get

Hence the radius of the planet is 3.4x 10^6 m

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To determine the maximum velocity at which you can make a turn without slipping in the rain at the intersection, we need to consider the changes in friction.

Let's assume the normal static friction and normal kinetic friction are represented by μs and μk, respectively.

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To avoid slipping during the turn, we need to ensure that the centripetal force required for the turn is less than or equal to the maximum frictional force available.

The centripetal force is given by the equation mv²/r, where m is the mass, v is the velocity, and r is the radius of the turn.

The maximum frictional force in the rain can be calculated as (0.5μs)mg, where g is the acceleration due to gravity.

Thus, to avoid slipping, we set the centripetal force equal to the maximum frictional force:

mv²/r = (0.5μs)mg

Simplifying the equation, we find:

v = √(0.5μsgr)

By plugging in the values for μs, g, and the radius of the turn, we can calculate the maximum velocity.

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The work done by lifting the suitcase is equal to 150 J.

Work can be explained as the energy utilized when a definite force is applied to move an object through a fixed displacement. The work done can be described as both the exerted force on the object and the displacement moved by the object.

The applied force is moved an object in the direction of the applied force over a displacement 'd'.

W= F × d

Given, the force applied on the suitcase to lift, F = 300N

The displacement  of the suitcase, d = 0.50 m

The work done can be calculated as:

W = F.d

W = 300 × 0.50

W = 150 J

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Using information from the NASA Institute for Space Studies The best representation of observed temperature increases in climate models is when orbital movements are taken into account.

What is climate model?

Hence solar variations, human-made aerosols, growth in greenhouse gas emissions, growth in greenhouse gas emissions is a correct answer.

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They are specifically made tο be ideal fοr cοnducting live electrical lines because οf their electrical insulatiοn and mechanical tοughness. A structure called an electric pylοn οf hοt-rοlled steel bevels οr gusset plates.

Other materials, such as cοncrete and wοοd, may alsο be utilised in additiοn tο steel. Transmissiοn tοwers can be divided intο fοur main categοries: suspensiοn, terminal, tensiοn, οr transpοsitiοn.

This Central Electricity Bοard held a cοmpetitiοn in 1927, and the winning entry was chοsen by the classical designer Sir Reginald Blοοmfield. He settled οn an A-frame structure with latticewοrk that was οffered by the American cοmpany Milliken Brοthers and is still in use tοday.

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Complete question:

The SI unit for the penetration coefficient of ultrasonic waves is m⁻¹.

option A is the correct answer.

Penetration coefficient describes the amount of particles reduced from the infiltration of outdoor particles due to the filtering effect of the building envelope.

Ultrasonic waves describes sound waves with frequencies higher than the upper audible limit of human hearing.

The SI unit of penetration coefficient of ultrasonic waves is expressed in either decibels per meter ( dB/mv ), or nepers per meter ( Np/m ) or equivalent to per meter ( m⁻¹ ).

Thus, the SI unit for the penetration coefficient of ultrasonic waves is per meter ( m⁻¹ ).

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False, the materials that are poor conductors are not poor insulators.

Materials that do not allow electricity to flow or pass through them, are called insulators or poor conductors of electricity. Electric charges are absent in Insulators, and they don't have free electrons in their outer orbits.

Similarly, Materials that do allow electricity to flow or pass through them, are called conductors or poor insulators of electricity. They conduct electricity because they have free electrons in their outer orbits, and also do have Electric charges.

Some common examples of conductors are copper, aluminum, and gold. Some common examples of insulators are glass, air, plastic, rubber, and wood.

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Answer:

Point C

Explanation:

Greatest Kinetic Energy means lowest potential energy since energy is conserved. Lowest potential energy means lowest height which is at Point C.

Answer:

15X30 + 3 e = 12Y30

Above an atom with 15 electrons (15 neutrons) accepts 3 electrons and thus reduces its charge by 3, but the number of neutrons remains the same

If the atom had a charge of 18 before accepting the electrons, it's charge would be reduced by three to 15

18X30 + 3e = 15Y30

From the question I am not sure the atomic number of 15 is before or after accepting the electrons

In any case the charge is reduced by three and the atomic mass is unchanged

Answer:

The net torque will be "1366.33 Nm".

Explanation:

The given values are:

Length of ladder,

\(\tau_{242N} = 9.83 \ m\)

then,

\(\tau=4.92\)

Mass,

= 20.3 kg

Now,

The net torque will be:

⇒  \(\tau_{net}=\tau_{mg}+\tau_{242}\)

On putting the given values, we get

⇒         \(=4.92\times (-mg)+9.83\times (+242)\)

⇒         \(=4.92\times (-21\times 9.8)+9.83\times 242\)

⇒         \(=-1012.53+2378.86\)

⇒         \(=1366.33 \ Nm\)

Birds underwent significant diversification and adaptation during the Mesozoic epoch, allowing them to develop into effective and adaptable flyers.

The wings of S. crossirostris, also referred to as the "delicate-winged pterosaur," were constructed of a delicate flap of skin called the patagium. This delicate membrane was prone to breaking, unlike the stiff feathers of birds.

In terms of flight prowess and ecological success, S. crossirostris would not have been able to compete with birds due to the restrictions imposed by its delicate wing structure.

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The  acceleration, tension of the cord between the 3.5 and 1 block, and the force excreted on the 2 block from the 1 block is 12.6 N.

To solve this problem, we need to apply Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

We can start by finding the acceleration of the system. Since the surface is frictionless, there are no horizontal forces acting on the blocks except for the tension in the string. Thus, we can write:

F - T = (m1 + m2 + m3) * a

where F is the force acting on the 3.5 kg block, T is the tension in the string between the 3.5 kg and 1 kg blocks, and a is the acceleration of the system. Substituting the values given in the problem, we get:

46 N - T = (1 kg + 2 kg + 3.5 kg) * a

46 N - T = 6.5 kg * a

Next, we need to find the tension in the string between the 3.5 kg and 1 kg blocks. This tension is the same throughout the string, so we can use the same equation we used to find the acceleration:

T - m1 * g = m1 * a

where g is the acceleration due to gravity (9.8 m/s^2). Substituting the values given in the problem, we get:

T - 1 kg * 9.8 m/s^2 = 1 kg * a

T = 1 kg * (a + 9.8 m/s^2)

Now, we can substitute this expression for T into the first equation we derived to get:

46 N - 1 kg * (a + 9.8 m/s^2) = 6.5 kg * a

Simplifying and solving for a, we get:

a = 2.84 m/s^2

Now that we know the acceleration of the system, we can find the force exerted by the 1 kg block on the 2 kg block. Since there are no horizontal forces acting on the 2 kg block, this force is equal in magnitude and opposite in direction to the force exerted by the 2 kg block on the 1 kg block. Thus, we can write:

F1-2 = -m2 * a

where F1-2 is the force exerted by the 1 kg block on the 2 kg block. Substituting the values given in the problem, we get:

F1-2 = -2 kg * 2.84 m/s^2

F1-2 = -5.68 N

Therefore, the force exerted by the 1 kg block on the 2 kg block is 5.68 N, directed to the left.

Finally, we can use the equation we derived earlier for the tension in the string to find the tension between the 3.5 kg and 1 kg blocks. Substituting the value we found for a, we get:

T = 1 kg * (2.84 m/s^2 + 9.8 m/s^2)

T = 12.6 N

Therefore, the tension in the string between the 3.5 kg and 1 kg blocks is 12.6 N.

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As water freezes below 4°C, the volume of the liquid shrinks and water molecule motion slows. When the temperature rises over 4 °C, the water molecules spread out and take up more space, increasing the volume.

Due to the peculiar property of water known as "Anomalous Expansion of Water," when 1 liter of water is cooled from 4°C to 0°C, the volume of the water starts to grow. Between 4°C and 0°C, water expands abnormally.

Water volume reduces as it is heated from 0°C to 4°C because the water's density will be maximum

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Answer:

I believe it is C, Potential

Explanation:

Google, since all types are either kinetic or potential, so it wouldn't make sense if kinetic was itself. I also know for a fact it isn't Chemical

Answer:

b

Explanation:

The answer is B. Why is the ocean floor not flat and smooth like the bottom of a bathtub?

Scientists were surprised to find that the ocean floor was not a flat and featureless plain, but rather had mountains, valleys, and other geological features. This discovery raised questions about how these features formed and what processes were involved. Scientists began to investigate the causes of these features, such as plate tectonics and volcanic activity, and how they might have shaped the ocean floor over millions of years. Understanding the complex and dynamic nature of the ocean floor has since become an important area of study in earth science and oceanography.

Answer:

energy transformation

Answer: Energy Transformation & Energy Conversion.

Explanation:

(i) The density bottle must be held by the neck to avoid expansion. (ii). The outside must be wiped clean. (iii).

Answer:

Explanation:

Time of flight = 1.6 s

Horizontal distance = 64 m

Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.

For the given case,

h = vt + ¹/₂gt²

h = height of tower

v = initial velocity

t = time of flight

55 = 50sin30t + ¹/₂9.8t²

55 = 25t + 4.9t²

4.9t² + 25t - 55 = 0

t = 1.6 s

X = vₓt

X = horizontal distance

vₓ = horizontal velocity

t = time of flight

X =  (50 x cos30) x 1.6

X =  64 m

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Answer:

A simple pendulum made up of a small suspended from a long thread of length I is set inte oscillation. If the period T of the oscillation is related to m, I and the acceleration due to gravity, g by the equation mass

k * m ^ x * P * y ^ z

T where x, y, z'and k are dimensionless constants, use dimensional analysis to obtain values of the constants x y, and z and hence an explicit expression for T.

Answer:

Explanation:

Let d be the distance to the center of mass from the front wheels

Sum moments about the front wheel contact point to zero

1240(9.8)[d] - 1240(9.8)(1 - 0.67)[3.2] = 0

1240(9.8)[d] = 1240(9.8)(1 - 0.67)[3.2]

                d = (1 - 0.67)[3.2]

                d = 1.056 m