two spherical nuclei with surface energy y having radii rl and r2 coalesce to form one spherical nucleus. if mass is conserved, calculate the energy reduction in the process.

Answer:

Lava dome

Explanation:

A geyser is hot water being shot up from the ground

A newly formed island would be somewhere on the ground not directly above  a volcano (Well depending on where the volcano is anyways)

A flood basalt plateau is like rocks I think?

Answer:

0.0001158443168226212 Celcius (significant digits? who cares.....) or about 0.00021 Fahrenheit

Explanation:

500g=0.5kg

PE=mgh

PE=(0.5)*(9.81)*(1.5)

PE=7.36J

3% of 7.36 is 0.22J is converted to heat

From there, it's tricky.

I just used a joules to celcius converter to get 0.0001158443168226212 degrees celcius or 0.00021 degrees fahrenheit rise in temp.

In microeconomics, both strong monotonicity and local non-satiation have different meanings and implications. Both terms refer to the preferences of the consumer. The two concepts are related but have some differences.

Let's define each term.

Strong monotonicity: Strong monotonicity is defined as a preference relation of a consumer, such that for any two bundles of goods, if bundle A has more of each good than bundle B, then the consumer strictly prefers A to B.

Local non-satiation: Local non-satiation implies that a consumer always prefers any bundle of goods that contains slightly more of any good than a different bundle, holding the other goods in the two bundles constant.

Now, we'll see that strong monotonicity implies local non-satiation but not vice versa.

Let's suppose a consumer has a preference for bundle A over bundle B if A has more of each good than B. This preference implies that if any good in bundle B is increased, the consumer will prefer the new bundle to the original bundle. This is a simple proof that strong monotonicity implies local non-satiation. If bundle A is preferred to bundle B due to monotonicity, then any bundle with a slightly higher quantity of any good in bundle A will also be preferred over B.

However, the reverse is not true. Local non-satiation does not imply strong monotonicity. Local non-satiation requires that the consumer prefers any bundle with slightly more of any good to a bundle with slightly less of any good. But this condition does not imply the monotonicity condition. For example, consider a preference relation such that the consumer prefers A to B and B to C, but prefers D to A.

This preference relation satisfies local non-satiation but not strong monotonicity because bundle D contains less of each good than A, but is preferred over A. Hence, strong monotonicity implies local non-satiation, but not vice versa.

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A change in the axon membrane potential from -70 mv to -90 mv would be termed as hyperpolarization.

Hyperpolarization occurs when the membrane potential becomes more negative than the resting potential. In this case, the membrane potential has decreased from -70 mv to -90 mv, indicating that the neuron has become more polarized or inhibited. The change in the membrane potential is caused by an increase in the permeability of the axon membrane to ions, which results in an efflux of positively charged ions, such as potassium, from the cell. This efflux of ions makes it more difficult for the neuron to reach its threshold potential and generate an action potential. Overall, hyperpolarization is an important physiological mechanism that allows neurons to maintain their resting potential and regulate their excitability.

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Answer:

Sunlight is a mixture of colors. When it passes through a glass prism, some of the light is bent, or refracted, more than other portions. And just as sunlight passing through a prism is bent, so is sunlight passing through drops of water. This produces an atmospheric solar spectrum in the sky for all to see: a rainbow.

Explanation:

Answer:

The moon doesn’t have light of its own, the moon lights up because of the sun. So at night, as the light of the sun doesn't reach the grass directly because of the moon, it doesnt reflect any color off the grass, and so our eyes detect grass as black.

Explanation:

Sun appears white, but it is made up of the colors: red, orange, yellow, green, blue, indigo, and violet. When white light hits an object, it absorbs some colors and reflect the others. Grass appears green because it absorbs all the wavelengths except green. Green is reflected off the grass, so we see grass as green.

Answer:

5.1 x 10¹⁰s

Explanation:

Given parameters:

Decay constant  = 13.6 x 10⁻¹²/s

Unknown:

Half life of the element  = ?

Solution:

From the decay constant, we can find the half-life of this radioactive element.

  Half-life  = \(\frac{0.693}{decay constant}\)  

     Half-life  = \(\frac{0.693}{13.6 x 10^{-12} }\)   = 5.1 x 10¹⁰s

With the application of third equation of motion, the car go as far as 451.3 meters before coming to a stop

Braking Force is the force applied for an object to decelerate or stop. It is also the product of mass and its deceleration.

Given that a car with a mass of 1260 kg is travelling at 38.0 m/s when the driver sees a traffic jam ahead. If the average braking force in modern vehicles is 2010 N,

The given parameters are;

Before we know how far will the car go before coming to a stop, we need to know its deceleration.

F = ma

2010 = 1260a

a = 2010/1260

a = 1.6 m/s²

Now, let us applied third equation of motion

v² = u² - 2as

v = 0 since the car is coming to rest.

0 = 38² - 2 × 1.6 × s

0 = 1444 - 3.2s

3.2s = 1444

s = 1444/3.2

s = 451.25 m

Therefore, the car go as far as 451.3 meters before coming to a stop.

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Therefore, the equation of motion for the mass-spring system is: x(t) = 12/√(5m) sin(√(5/m)t + tan⁻¹(√(5)))

We can start by finding the spring constant, k, using Hooke's law:

F = kx

where F is the force applied to the spring and x is the resulting displacement. Rearranging, we get:

k = F/x = 720 N / 4 m = 180 N/m

Now, we can use Newton's second law of motion to find the equation of motion for the mass-spring system:

F_net = ma

where F_net is the net force acting on the system, m is the mass, and a is the acceleration. The net force in this case is the sum of the force from the spring and the force due to gravity:

F_net = -kx + mg

where g is the acceleration due to gravity. Substituting in our values:

F_net = -180x + (45 kg)(9.8 m/s²)

= 441 - 180x

Now, we can rewrite Newton's second law as a differential equation:

= 441 - 180x

Simplifying and rearranging:

d²x/dt² + (180/m)x

= 441/m

The characteristic equation is:

r² + (180/m) = 0

with roots:

r = ±√(-180/m)

Since m > 0, the roots are imaginary, which means that the general solution to the differential equation is:

x(t) = A cos(ωt) + B sin(ωt) + C

where A, B, and C are constants and ω is the angular frequency. To find the values of these constants, we need to use the initial conditions. At t = 0, x = 0 and dx/dt = 12 m/s. Therefore:

x(0) = A + C = 0

dx/dt|_(t=0) = ωB = 12 m/s

Solving for A, B, and ω:

A = -C

B = 12/ω

ω = 12/B

= 12/(12√(-180/m))

= √(-5/m)

So, the general solution becomes:

x(t) = A cos(√(-5/m)t) + B sin(√(-5/m)t) - A

We can find the value of A using the fact that the maximum displacement occurs when the velocity is zero:

tan(√(-5/m)t) = A/B

At the maximum displacement, tan(sqrt(-5/m)t) = infinity, so A/B must be negative. Therefore:

A = -B = -12/sqrt(-5/m)

Simplifying and using the identity cos(α - β) = cos(α)cos(β) + sin(α)sin(β):

x(t) = 12/√(5m) sin(√(5/m)t + tan⁻¹(√(5)))

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The man has a maximum time of approximately 1.979 seconds to get out of the way before the cement block reaches the ground.

To determine the maximum time the man has to get out of the way, we need to calculate the time it takes for the cement block to fall from a height of 19.2 m to the ground.

The time it takes for an object to fall freely under gravity can be found using the equation:

h = (1/2) * g * t^2

where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.

Rearranging the equation, we get:

t = sqrt(2h/g)

Plugging in the values, we have:

t = sqrt(2 * 19.2 / 9.8)

t ≈ sqrt(3.918)

t ≈ 1.979 seconds

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Answer:

1)  v = 1.19 m / s , 2)     P₁ = 9.308 10⁴ Pa  

Explanation:

In this exercise we will simulate the emission of urine as a fluid mechanics system

1) they indicate the urine flow rate Q = 0.0060 m³ / s, they also give the diameter of the tube 8.0 cm, they ask us the speed.

   Let's use the continuity equation

            Q = v A

The area of ​​a cycling tube is

            A = π r² = π d² / 4

we substitute

            Q = v π d² / 4

            v = 4Q / π d²

let's calculate

            v = 4 0.006 / (π 0.08²)

            v = 1.19 m / s

2) they ask to find the pressure in the bladder, for this we use the Bernoulli equation, where the index is for the bladder and the index 2 is for the exit point

            P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

in the exercise it indicates that the outlet pressure is equal to the atmospheric pressure P₂ = 1,013 10⁵ Pa, the velocity of the liquid in the bladder is v₁ = 0 and the height difference 1.0 m

           P₁ = P₂ + ½ ρ v₂² + ρ g (y₂-y₁)

let's calculate

          P₁ = 1.013₁ 10⁵⁵ + ½ 1000 1.19 + 1000 9.8 (0-1)

          P₁ = 1.013 105 + 595 - 9800

          P₁ = 9.308 10⁴ Pa

The frictional force reduces the block's kinetic energy and causes negative work to be done on it.

Kinetic energy is the energy that a thing has when it is moving. An item can only be accelerated through the application of a force. Applying force requires effort on our part. Following completion of the work, energy is transferred towards the object, which then moves at such a new, constant speed.

Kinetic energy appears to be the driving force behind motion, as evidenced by the way objects and subatomic particles move. Every particle & moving object contains kinetic energy. Examples of kinetic energy in motion include walking, a baseball flying through the air, food falling off a table, and just a charged particle within an electric field.

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The average emf induced in the wire loop during the extraction process is 0.0401 V.

The average emf induced in a wire loop is given by Faraday's law of electromagnetic induction:

emf = -N * d(ΦB)/dt

Where:

emf is the electromotive force (induced voltage)

N is the number of turns in the loop

d(ΦB)/dt is the rate of change of magnetic flux through the loop

In this case, we have a circular loop of wire with a radius of 12.0 cm, so the area of the loop (A) is given by:

A = π * (radius)^2

A = π * (0.12 m)^2

The magnetic field (B) is given as 1.7 T, and the time interval for the extraction process (dt) is 2.1 ms, which is equal to 2.1 × 10^(-3) s.

The rate of change of magnetic flux (d(ΦB)/dt) can be calculated by multiplying the magnetic field (B) by the area (A) and the rate of change of time (dt):

d(ΦB)/dt = B * A * dt

Substituting the given values:

d(ΦB)/dt = 1.7 T * π * (0.12 m)^2 * (2.1 × 10^(-3) s)

Now we need to determine the number of turns in the loop (N). Since the problem statement doesn't provide this information, we'll assume there is only one turn in the loop, which gives us:

N = 1

Finally, substituting the values of N, d(ΦB)/dt, and using the negative sign to indicate the direction of the induced current, we can calculate the average emf (E):

emf = -N * d(ΦB)/dt

emf = -1 * (1.7 T * π * (0.12 m)^2 * (2.1 × 10^(-3) s))

Simplifying the expression:

emf = -0.0401 V

Therefore, the average emf induced in the wire loop during the extraction process is 0.0401 V.

During the extraction process, the average emf induced in the wire loop is 0.0401 V.

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Minimum angular separation: 0.06 degrees for 21-cm wavelength, 200-m telescope.

The minimum angular separation resolvable by a radio telescope can be determined using the formula:

θ = λ / D,

where θ is the angular separation, λ is the wavelength of the radiation, and D is the diameter of the telescope.

In this case, the wavelength (λ) is given as 21 cm, and the diameter of the telescope (D) is 200 m.

Converting the wavelength to meters:

λ = 21 cm = 0.21 m.

Substituting the values into the formula:

θ = 0.21 m / 200 m.

Calculating the result:

θ = 0.00105 radians.

To express the result in degrees, you can convert radians to degrees using the conversion factor: 1 radian = 57.3 degrees.

θ = 0.00105 radians \(*\) 57.3 degrees/radian.

θ ≈ 0.06 degrees.

Therefore, the minimum angular separation resolvable by the 200-m radio telescope for sources emitting a 21-cm wavelength is approximately 0.06 degrees.

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5.45 cm to the right of the second lens is where the final image is created.

The image will get smaller and smaller as we move the object further and further away. The focal point will draw the image's location ever-closer. The light would be concentrated at the focal point if the object were extremely far away, such as the sun.

Using the thin lens equation, we have: 1/f = 1/di + 1/do

For the first lens, we have:

f1 = -6.00 cm (negative because the lens is diverging)

do1 = -10.0 cm (negative because the object is to the left of the lens)

Solving for di1, we get: 1/di1 = 1/f1 - 1/do1

di1 = -15.0 cm (negative because the image is to the left of the lens)

The first lens creates a virtual, upright image whose magnification is determined by: m1 = -di1/do1 = 1.50

As there are 4.50 cm between the first and second lenses, the location of the thing that the second lens sees is:

do2 = di1 - 4.50 cm = -19.5 cm

For the second lens, we have:

f2 = 6.00 cm (positive because the lens is converging)

do2 = -19.5 cm (negative because the object is to the left of the lens)

Solving for di2, we get:

1/di2 = 1/f2 - 1/do2

di2 = 5.45 cm

The final image is real and inverted, and its magnification is given by:

m = -di2/do2 = 0.279

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Answer:

its 4 right

i hope it is

Answer:

im pretty positive its 4 , if not its 1

Answer:

a

Explanation:

The compound that is more polar is diacetylferrocene.

Ferrocene is a non-polar compound because it has a symmetrical structure, with two cyclopentadienyl rings bonded to a central iron atom. Acetylferrocene is more polar than ferrocene because it has an acetyl group attached to one of the cyclopentadienyl rings, which introduces some polarity to the molecule.

However, diacetylferrocene is the most polar of the three compounds because it has two acetyl groups attached to the cyclopentadienyl rings, which increases the polarity of the molecule even further.
In summary, the order of polarity for these compounds is: ferrocene < acetylferrocene < diacetylferrocene.

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The components of the velocity vector in the northerly and westerly directions are approximately 77.46 km/h and 91.89 km/h respectively.

The problem is to determine the components of the velocity vector in the northerly and westerly directions. Let's say we have the velocity vector V. And, the angle between V and the west is θ.

Then, we can say that the component of V in the westerly direction is given by V_w= V cosθSimilarly, if the angle between V and the north is θ, then the component of V in the northerly direction is given by V_n= V sinθ.

Now, let's see how we can apply these formulas to solve the problem.

We can start by sketching the velocity vector V on the x-y plane, with the tail of the vector at the origin.  \((V = 120 km/h, θ = 40°)\) .

Then, we can find the components of V in the northerly and westerly directions as follows:  \(V_n= V sinθ= 120 sin40° ≈ 77.46 km/h\) \(V_w= V cosθ= 120 cos40° ≈ 91.89 km/h\).

Thus, the components of the velocity vector in the northerly and westerly directions are approximately 77.46 km/h and 91.89 km/h respectively.

To summarize the steps involved, we first sketched the velocity vector V on the x-y plane. Then, we used the formulas V_w= V cosθ and V_n= V sinθ to find the components of V in the westerly and northerly directions. Finally, we substituted the given values of V and θ to obtain the numerical values of the components.

In conclusion, the velocity vector can be broken down into its components in the northerly and westerly directions using the formulas V_w= V cosθ and V_n= V sinθ. We can then substitute the given values of V and θ to obtain the numerical values of the components.

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Given data

*The given frequency is

*The another given frequency is

*The given speed of light is c = 3.0 × 10^8 m/s

(a)

The formula for the wavelength is given as

Substitute the known values in the above expression as

The another wavelength for the another frequency is calculated as

(b)

Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.

The best way to find the exact distance to the moon is by using the Lunar Laser Ranging (LLR) technique.The Lunar Laser Ranging (LLR) technique is currently the most accurate method for determining the distance between the Earth and the Moon.

This technique involves firing a laser beam from a ground-based observatory at a retroreflector array placed on the Moon by astronauts during the Apollo missions. The laser beam is reflected back to Earth, and the time it takes for the light to travel to the Moon and back is measured with extremely high precision.

By measuring the round-trip time of the laser beam and taking into account the speed of light, scientists can calculate the distance between the Earth and the Moon with an accuracy of a few millimeters. This technique has been used for over 50 years and has provided invaluable data for studying the dynamics of the Earth-Moon system, including the moon's orbit and rotation, and the tides on Earth. The LLR technique has also helped to test the theory of gravity, and has provided constraints on the masses of the Earth, Moon, and other objects in the solar system.

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Answer:

most likely it will stay the same

Answer:

he is right it’s D

Explanation:

if u could not read his hand writing

Answer:

15,115 J of the total energy is transformed to thermal energy during the game.

Explanation:

From the law of conservation of energy, initial energy of the closed system E = final energy of closed system , E'

E = E'.

Let ME = initial mechanical energy of the system = 16,250 J and U = initial internal energy of the system and ME' = Final mechanical energy of the system = 1,135 J and U' = Final internal energy of the system.

So E = ME + U and E' = ME' + U'

We now find U and U'

Substituting E, ME, E' and ME' into the equations, we have

E = ME + U

17,125 J = 16,250 J + U

U = 17,125 J - 16,250 J

U = 875 J

E' = ME' + U'

17,125 J = 1,135 J + U'

U' = 17,125 J - 1,135 J

U' = 15,990 J.

The change in internal energy is also the change in thermal energy. So,

ΔU = U' - U

ΔU = 15,990 J - 875 J

ΔU = 15,115 J

So 15,115 J of the total energy is transformed to thermal energy during the game.

Answer:

D. chemical control

Explanation:

The reason for using chemical control as last resort in IPM is:

1) Impact is very high

2) The response is immediate

We find that the change in kinetic energy is positive and equal to 696.60 W, option d. The formula for kinetic energy is given by KE = 1/2 * mv^2, where m is the mass of the fluid and v is its velocity.

In this case, we are given the velocities at the outlet and the reactor inlet, which are 14.4 m/s and 10.7 m/s, respectively. Since the mass of the fluid is not provided, we can assume it to be constant.

The change in kinetic energy is given by the difference in kinetic energies at the outlet and the reactor inlet, which can be calculated using the formula:

ΔKE = (1/2 * m * v_outlet^2) - (1/2 * m * v_inlet^2)

Simplifying this expression, we get:

ΔKE = 1/2 * m * (v_outlet^2 - v_inlet^2)

Plugging in the given values, we have:

ΔKE = 1/2 * m * (14.4^2 - 10.7^2)

Calculating this expression, we find the answer to be approximately 696.60 W. Therefore, the correct option is d. 696.60.

In summary, the change in the rate of kinetic energy is approximately 696.60 W. This is calculated by taking the difference between the kinetic energy at the outlet and the kinetic energy at the reactor inlet using the formula ΔKE = 1/2 * m * (v_outlet^2 - v_inlet^2). Plugging in the given velocities of 14.4 m/s and 10.7 m/s, we find that the change in kinetic energy is positive and equal to 696.60 W.

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Answer:

D.

Driving and talking on any type of cell phone increases the chance of missing traffic signals.

Explanation:

correct on edge2021

Answer:

the answer is d thank me later

Explanation:

In most cases, when wave refract, frequency and amplitude will be constant while wavelength and speed will change.

The four properties of waves are:

When a wave moves from one medium to another, the wave will undergo refraction.

When a wave move for instance, from water to glass, the wave will refract by changing direction. In most scenario, the frequency of the wave will be constant while the wavelength of the wave will change. Since the wavelength will change, the speed will also change.

Therefore, when a wave moves from one medium to another, the properties of the wave that change are wavelength and wave speed.

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Answer:

At position "B" the northern hemisphere is tilted the most from the earth-sun direction and will experience the shortest hours of daylight, (and also the most indirect sun rays).

Answer:

Because the hot tea is hot from a microwave or coffee machine when iced tea is cold from ice in the tea.

Explanation: