Answer: When work is positive, the environment does work on an object
Explanation:
The correct option is a)When work is positive, the environment does work on an object.
What is positive and negative work done ?
If work is done on the system , positive work is done on the system because energy enters the system in case of positive work done .If work is done by the system , work done will be negative
According to work energy theorem , change in kinetic energy is equal to work done . when energy enters in the system that means final energy is greater than the initial energy of the system , which implies positive work is done on an object .
this implies , correct option is a)When work is positive, the environment does work on an object.
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State the law of gravity, and explain how this paper airplane investigation
proved Newton's law of gravity.
Based on Newton's law of gravity, the force of attraction on the airplane moving on Earth is directly proportional to the mass of the airplane and inversely proportional to the square of distance the airplane from Earth's surface.
What is Newton's law of universal gravitation?
Newton's law of universal gravitation states that the force of attraction between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects.
Mathematically, this law is written as follows;
Fg = ( G m₁ m₂ ) / ( r² )
where;
G is the universal gravitation constantm₁ is the mass of the first objectm₂ is the mass of the second objectr is the distance between the two objectsFrom Newton's second law of law of motion we will have;
F = mg
mg = ( G m₁ m₂ ) / ( r² )
g = Gm / r²
Every object on Earth surface moves with equal acceleration due to gravity which has a value of 9.8 m/s².
Thus, airplane flying on Earth surface will be affected by gravity and the weight or downward force on the airplane is a function of gravity.
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A toy car has a 1. 5-a current, and its resistance is 2. How much voltage does the car require? v.
The voltage required by the toy car is 3 volts.
Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R). Mathematically, it can be expressed as:
V = I * R
In this case, we are given that the current (I) flowing through the toy car is 1.5 A (amperes), and the resistance (R) of the car is 2 Ω (ohms).
Substituting these values into the equation, we can calculate the voltage (V) required by the car:
V = 1.5 A * 2 Ω
V = 3 V
So, the voltage required by the toy car is 3 volts. This means that to operate the toy car properly, a power source or battery with a voltage output of 3 volts is needed.
The voltage provides the electrical potential necessary for the current to flow through the car's circuit, overcoming the resistance and powering the car's motor or other components.
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what happens the first time dr. hewitt lifts the bowling ball near his teeth and lets go?
Dr. Hewitt's experiment using the bowling ball to showcase the relationship between momentum, energy and speed of a body in motion. In his first attempt, the ball returns and stops almost exactly at the point it was launched.
In Dr.Hewitt's first trial with the bowling ball, the ball was launched without any additional force applied, hence, the initial energy during the launch was converted to same amount of potential energy on the ball's return. Hence, stopping at the same point where the ball was launched. In subsequent trials, when extra force was applied, the ball went past the initial launch position as the potential energy as the ball returned was higher.Therefore, the ball stopped at the position of initial launch during the first trial.
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Calculate the coefficient of linear expansion a for a 16.0 m metal bar that shortens by 0.700 cm when the temperature drops from 30.0 °C to 8.00 °C. α = x10-6K-1
The coefficient of linear expansion (α) can be calculated using the following formula:α = ΔL / LΔTWhere:ΔL = change in length L = original lengthΔT = change in temperatureGiven:ΔL = 0.700 cm = 0.007 mL = 16.0 mΔT = 30.0 °C - 8.00 °C = 22.0 °C Converting ΔT to Kelvin scale:ΔT = 22.0 °C = 22.0 K
The formula can now be rewritten as:α = ΔL / LΔTα = 0.007 m / 16.0 m × 22.0 Kα = 0.000002534 K^(-1)α = 2.534 × 10^(-6) K^(-1)Therefore, the coefficient of linear expansion (α) for the given metal bar is 2.534 × 10^(-6) K^(-1).
A material's length change in response to a change in its temperature is measured by a coefficient of thermal expansion, which is typically represented by the symbol. The length change of a material is inversely proportional to its temperature change under small temperature changes.
V = VT, where is the volume expansion coefficient and 3 is the volume change caused by thermal expansion. At the point when the warm development is limited, warm pressure is created. The coefficient of warm extension equation makes sense of how an item's size increments as the temperature changes.
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(Newton's Law of Cooling): The mathematical formulation of Newton's empirical law of cooling/warming of an object is given by the linear first-order differential equation
dt
dT
=k(T−T
s
), where k is a constant of proportionality, T(t) is the temperature of the object at any time t≥0, and T
s
is the surrounding environmental temeperature, that is, the temperature of the medium around the object. (i). Assuming that T
s
is constant, find the temeperature of the object as a function of time if T(0)=T
0
. (ii). Then what is the temepretauer of the object after 5 minutes?
Newton's Law of Cooling is described by the first-order linear differential equation dt/dT = k(T - Ts), where T(t) is the temperature of the object at time t, Ts is the surrounding environmental temperature, and k is the constant of proportionality.
The temperature of an object, governed by Newton's Law of Cooling
(i) To find the temperature of the object as a function of time, we first solve the differential equation dt/dT = k(T - Ts). This is a separable differential equation, and the solution can be obtained by rearranging and integrating:
dt/dT = k(T - Ts)
dt = k(T - Ts) dT
∫ dt = ∫ k(T - Ts) dT
t = k * ∫ (T - Ts) dT
t = k * (T^2/2 - Ts*T) + C
Now, we apply the initial condition T(0) = T0. At t=0, the temperature of the object is T0:
T(0) = T0
k * (\(T0^2\)/2 - Ts*T0) + C = T0
C = T0 - k * (\(T0^2\)/2 - Ts*T0)
C = T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2
C = T0 - k * (\(T0^2\) - 2 * Ts * T0) / 2
So, the equation becomes:
t = k * (\(T^2\)/2 - Ts*T) + (T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2)
(ii) Now, we can find the temperature of the object after 5 minutes (t = 5 minutes). We'll use the initial condition T(0) = T0 and the formula obtained in part (i):
t = 5 minutes = 5/60 hours = 1/12 hours
T(t) = Ts + (T0 - Ts) * exp(-kt)
T(1/12) = Ts + (T0 - Ts) * exp(-k * (1/12))
This equation gives us the temperature of the object after 5 minutes, considering the given initial temperature T0 and the surrounding environmental temperature Ts.
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What is the density of a box measuring 100 grams and 10 ml?
Answer:
In order to convert density to grams, you have to put the mass on one side of the equation, and the density and the volume on the other. Therefore, d * v = m. Multiply the density by the volume. Using the example in step 1, you would multiply 2 g/mL by 4mL.
Explanation:
ok
You stand 280 cm away from a tuning fork emitting a sound with 7.6 x 10^-4 w of
power. what is the intensity of the sound you hear?
The intensity of the sound you hear at a distance of 280cm away from the tuning fork is 7.72 x 10⁻⁶ W/m².
What is sound intensity?The power carried by sound waves per unit area in a direction perpendicular to that area.
It is defined as the ratio of power and area.
I = P / 4πr²
Given is the radius 280 cm = 2.8 m and power 7.6 x 10⁻⁴ watt, then the sound intensity is
I = 7.6 x 10⁻⁴ / (4 x 3.14 x 2.8²)
I = 7.72 x 10⁻⁶ W/m²
Thus, the intensity of the sound you hear at a distance of 280cm away fr0om the tuning fork is 7.72 x 10⁻⁶ W/m².
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a highly charged child's balloon is not dangerous because group of answer choices its outside surface is positively charged. rubber is not a good conductor of electricity. the potential difference between the balloon and the child's hand is very small. none of the above choices are correct.
A highly charged child's balloon is not dangerous because none of the above choices are correct
Since The static electricity in a balloon cannot harm you, though it can give you an annoying jolt. Static electricity is a gathered charge caused by an imbalance of electrons and protons on things around us. Rubbing two materials together may quagmire off a particle or two as they touch. This makes an imbalance in one of the materials, which sits there holding up for an opportunity to adjust itself when something with a comparing lopsidedness comes near sufficient. The adjusting release causes a pop of electricity or an inactive release. Since this voltage is fair sitting there's, it called static. Because it looks to move to something else, the movement classifies it as current electricity, and not static. Static power within the off-base situations, in any case, may be unsafe. A few areas have a solid reason for disposing of these small charges.
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4. What evidence do scientists have that lead them to believe there is a black hole at the center of the milky way?
A) they have directly measured the gravity of the black hole.
B) they have observed the very rapid orbits of stars close to the area.
C) they have observed comets and asteroids disappearing into the area.
D) they have sent a probe into the area and it did not return.
5. About how much of the mass of the Milky way has yet to be discovered by scientists?
A) 95%
B) 70%
C) 20%
D) 5%
4. B They have observed the very rapid orbits of stars close to the area.
5. A. 95%
im doing the test right now
- A periodic composite signal with a bandwidth of 2000 Hz is composed of two sine waves. The first one has a frequency of 100 Hz with a maximum amplitude of 20 V; the second one has a maximum amplitude of 5 V. Draw the bandwidth. - A TV channel has a bandwidth of 6MHz. If we send a digital signal using one channel, what are the data rates if we use one harmonic, three harmonics, and five harmonics?
The bandwidth of the periodic composite signal is drawn as a range between 100 Hz and 2100 Hz , The data rates for sending a digital signal using one harmonic, three harmonics, and five harmonics on a TV channel with a 6 MHz bandwidth would be 6 MHz, 18 MHz, and 30 MHz .
For the first question
Draw the bandwidth of a periodic composite signal, we need to consider the highest frequency component present in the signal.
We have two sine waves one with a frequency of 100 Hz and the other unspecified. Since the bandwidth is given as 2000 Hz, we can assume that the second sine wave has a frequency of 2100 Hz (2000 Hz above the first sine wave frequency).
Draw the bandwidth, we can create a graph with frequency on the x-axis and amplitude on the y-axis.
We plot the amplitude values for the two sine waves at their respective frequencies (100 Hz and 2100 Hz). The bandwidth will be the range between these two frequencies on the x-axis.
For the second question
The data rate for a digital signal transmitted using one harmonic, three harmonics, and five harmonics can be calculated by multiplying the channel bandwidth by the number of harmonics used. Since the bandwidth is given as 6 MHz, the data rates would be as follows:
One harmonic: 6 MHz
Three harmonics: 18 MHz
Five harmonics: 30 MHz
The data rate increases with the number of harmonics used because each harmonic contributes additional information to the signal, allowing for a higher data transmission rate.
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Help please!!!
Do you think we always see the same side of the Moon?
Answer:
yess
Explanation:
"The Moon orbits Earth once every 27.3 days and spins on its axis once every 27.3 days. This means that although the Moon is rotating, it always keeps one face toward us. Known as “synchronous rotation,” this is why we only ever see the Moon's nearside from Earth."
A circus cat has been trained to leap off a 12-m-high platform and land on a pillow. The cat leaps off at
v0 = 3.7 m/s
and an angle
theta = 34°
(see figure below).
(a) Where should the trainer place the pillow so that the cat lands safely?
d = m
(b) What is the cat's velocity as she lands in the pillow? (Express your answer in vector form.)
vf = m/s
To ensure that the circus cat lands safely on the pillow, we need to determine the horizontal distance the trainer should place the pillow and the cat's velocity as she lands.
(a) To find the horizontal distance (d), we can use the projectile motion equations. The cat's initial vertical velocity (v0y) can be calculated by multiplying the initial velocity (v0) by the sine of the launch angle (θ). So, v0y = v0 * sin(θ).
Next, we can use the equation for horizontal distance traveled (d) in projectile motion, which is given by d = v0x * t, where v0x is the initial horizontal velocity and t is the time of flight. The initial horizontal velocity (v0x) is calculated by multiplying the initial velocity (v0) by the cosine of the launch angle (θ).
Since the cat lands on the same horizontal level as it starts, the time of flight can be determined using the vertical motion equation h = v0y * t - 0.5 * g * t^2, where h is the initial vertical height (12 m) and g is the acceleration due to gravity (9.8 m/s^2). Solve this equation to find the time of flight (t).
Once you have the time of flight, you can calculate the horizontal distance (d) using the equation d = v0x * t.
(b) To find the cat's velocity (vf) as she lands in the pillow, we can use the components of velocity. The final vertical velocity (vf_y) is given by vf_y = v0y - g * t. The final horizontal velocity (vf_x) remains constant throughout the motion.
The magnitude of the final velocity (vf) can be calculated using the Pythagorean theorem, which is vf = sqrt(vf_x^2 + vf_y^2). The direction of the velocity can be determined by finding the angle (θ_f) using the arctan function, which is θ_f = arctan(vf_y / vf_x).
In vector form, the cat's velocity as she lands will be expressed as vf = vf_x i + vf_y j, where i and j are unit vectors in the x and y directions, respectively.
Remember to use appropriate units and plug in the given values to obtain numerical answers.
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Suppose you mount a baseball machine that fires balls straight up in the air at 96ft/s on top of a 52-foot tall building. What is the velocity of one of these baseballs when it hits the ground
The velocity of one of these baseballs when it hits the ground is 76.73 ft/s.
What is meant by velocity?Velocity is the directional speed of any object in motion as an indication of rate of change in position as observed from the particular frame of reference and as measured by the particular standard of time.
Let the final velocity be v
Given, initial velocity, u = 96 ft/s
g = 32 ft/s²
Given height, h = 52 feet
As we know, v² = u² - 2 g h
So, v² = 96 x 96 - 2 x 32 x 52
v = 76.73 ft/s
So, the speed of the ball as it hits the ground is 76.73 ft/s.
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I need help ASAP ANYONE
10% of more girls are likely to work than boys.
option A.
What is the percentage of the boys and girls that work?The percentage of girls who are more likely to work than boys are calculated as follows;
Total number of boys = 18 + 12 = 30
Number of boys who works = 18
Percentage = 18/30 x 100% = 60%
Total number of girls = 14 + 6 = 20
Number of girls who works = 14
Percentage = 14/20 x 100% = 70%
Difference = 70% - 60% = 10%
So 10% of more girls are likely to work than boys.
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Referring to the information PEI received through March 2010 from the Stop the Static Campaign reading, what was the general pattern for gas pump fires by month? Why do you think this trend
emerged?
The common cause for gas pump fires is static electrical discharge.
What is static electricity?Static electricity is an imbalance of electric charges within or on the surface of a material or between materials.
In petrol pumps,
During refueling, many petroleum products become electrically charged when they flow through pipes and hoses, including gasoline, kerosene, petrol, diesel etc. which are poor electrical conductors.
Charge remains until it is able to move away by means of an electric current or electrical discharge which causes the static spark that can ignite gasoline vapors, causing a flash fire.
Hence, static electrical discharge is common cause of gas pump fires.
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A car moving at a speed of 20m/s has a kinetic energy of 300,000 J what’s the cars mass
Answer:
1500 kgExplanation:
The mass of the car can be found by using the formula
\(m = \frac{2k}{ {v}^{2} } \\ \)
From the question we have
\(m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ \)
We have the final answer as
1500 kgHope this helps you
A person starts at a position of 16 meters and finishes at a position of
2 meters. The trip takes 4 seconds. What is the person's average
velocity?
3.5 m/s
-3.5 m/s
6.0 m/s
-6.0 m/s
Answer:
38 is a good girl and a great place to work for u and I miss you y and I miss you much love your love and love to
i truly need help with these 10 questions , it soo late and i only have 2 days too turn it in please anybody help me !!
characteristics of radiation from the sun's energy would be
A. heat from a distance source, elcetromagnatic waves and energy that travels through space.
B. Direct contact of the energy source of sufaces
C. Movement of heat through fluids
WHICH ONE IS THE ANSWER HELPPP
Answer:
Answer is A
Explanation:
A spring is hung from the ceiling. A 0.442-kg block is then attached to the free end of the spring. When released from rest, the block drops 0.150 m before momentarily coming to rest, after which it moves back upward. (a) What is the spring constant of the spring
Answer:
\(K=58.8N/m\)
Explanation:
From the question we are told that:
Mass \(M=0.442\)
Drop distance \(d=0.150\)
Generally the equation for Spring Constant is mathematically given by
\(K=\frac{2mg}{x}\)
\(K=\frac{2*0.442*9.8}{1.150}\)
\(K=58.8N/m\)
During first half of a journey by a body it travel with a speed of 40km/hr and in the next half it travels with a speed of 20 km/hr .Calculate the average speed of the whole journey.
Answer:
Average speed = 26.67 km/h
Explanation:
It is given that,
The first half of the journey by a body is traveled with a speed of 40 km/h and the next half is covered with a speed of 20 km/h
We need to find the average speed of the whole journey. When two speeds are given, the average speed is given by :
\(v=\dfrac{2v_1v_2}{v_1+v_2}\\\\v=\dfrac{2\times 40\times 20}{40+20}\\\\v=26.67\ km/h\)
So, the average speed of the body of the whole journey is 26.67 km/h.
if you were given a rock sample and told it contained 200 atoms and three half-lives had passed how much of the daughter isotope would you have? How much of the parent isotope?
After three half-lives, 1/8 (or 0.125) of the parent isotope remains. Thus, 0.125 times the parent atoms. The daughter isotope would be equivalent to the remaining parent isotope, 0.125 times the original number of parent atoms.
After three half-lives, the parent isotope has exponentially decayed, forming the daughter isotope. Each half-life reduces the parent isotope by half and increases the daughter isotope. Three half-lives have passed, reducing the parent isotope to 1/8 of its initial level. The rock sample would have 1/8 of the parent isotope.
The daughter isotope would have accumulated during decay. After three half-lives, the daughter isotope would have reached 3/8 of the parent isotope as each half-life creates one-half of it. After three half-lives, the rock sample would have 1/8 of the parent isotope and 3/8 of the daughter.
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The time for a sound wave to travel between two people is 0.80 s,
The people are 256 m apart
Calculate the speed of sound in air.
Answer:
Explanation:
Using the below formula
Speed of sound = ( distance between observers) *2/(total time taken)
Now putt the given values ,
time taken = 0.80 sec
distance = 256 m
hence
V of sound= 256*2/0.80
V of sound = 640 m/sec
why were the fastest climbers not necessarily the ones who developed the most power
The fastest climbers are not necessarily the ones who developed the most power because power is not determined by the speed of an object.
When we talk mathematically the power in an object is defined as the work done by the body per unit time.
The fastest climber necessary for the ones who developed the most power because a greater velocity or a greater speed is not a parameter for calculating the power in an object or in our body.
The power is only calculated on the basis of the work done by a climber.
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how much work is done by the engine of a 1.6t (1600kg) car if the car covers the first 250m after departure in 30s, the coefficient of friction between the wheels and the ground is 0.03?
Answer:
To determine the work done by the engine of the car, we need to calculate the net work done on the car during the motion. The net work is given by the change in kinetic energy of the car:
net work = (1/2)mvf^2 - (1/2)mvi^2
where m is the mass of the car, vi is the initial velocity of the car, and vf is the final velocity of the car.
To calculate the final velocity of the car, we can use the equations of motion:
vf = vi + at
x = vi*t + (1/2)at^2
where x is the distance traveled by the car, a is the acceleration of the car, and t is the time taken to cover the distance x.
Using the given values of x = 250 m and t = 30 s, we can solve the second equation for a:
a = 2(x - vi*t) / t^2
where vi can be assumed to be zero since the car starts from rest. Substituting the given values, we get:
a = 2(250 m)/ (30 s)^2 = 0.3704 m/s^2
Now, we can use the coefficient of friction between the wheels and the ground to calculate the force of friction acting on the car:
f_friction = friction coefficient * normal force
where the normal force is the weight of the car, given by:
normal force = m * g
where m is the mass of the car and g is the acceleration due to gravity.
Substituting the given values of m = 1600 kg, g = 9.8 m/s^2, and the given coefficient of friction, we get:
f_friction = 0.03 * 1600 kg * 9.8 m/s^2 = 470.4 N
The force of friction acts in the opposite direction to the motion of the car, so we can find the net force acting on the car:
net force = f_engine - f_friction
where f_engine is the force generated by the engine of the car. We can assume that the force generated by the engine is constant, so we can use the equation:
f_engine = m * a
where m is the mass of the car and a is the acceleration of the car.
Substituting the given values of m = 1600 kg and the calculated value of a = 0.3704 m/s^2, we get:
f_engine = 1600 kg * 0.3704 m/s^2 = 592 N
Now we can find the net work done on the car by substituting the calculated values of f_engine and f_friction into the equation for net force:
net force = f_engine - f_friction = 592 N - 470.4 N = 121.6 N
The net work done on the car is then given by:
net work = net force * x
Substituting the given value of x = 250 m and the calculated value of net force, we get:
net work = 121.6 N * 250 m = 30,400 J
Therefore, the work done by the engine of the car is approximately 30,400 J.
Treatment for Common Sports Injuries
Practice
Active
b 21 (3
Explain why the first step in responding to any sports injury is to remove the danger that led to the injury
11. A car travels 100 km. The journey takes two hours. The highest speed of the car is
80 km/h,
and the lowest speed is 40 km/h.
What is the average speed for the journey?
A 40 km/h
B 50 km/h
C 60 km/h
D 120 km/h
Answer:
B
Explanation:
100km/2h = v
50km/h = v
Hope that helps
Answer:
50 km/h
Explanation:
Because if it traveled 100 km/h and took 2 hrs. then 50 km/h + 50 km/h = 100 km/h
please let me know if I was right. Have a good night :)
A device sends out waves with frequency of 68. 0 Hz and a wavelength of 28. 0 m. What are the speed of those sound waves?
Those sound waves travel at a speed of 1904 meters per second.
The equation for velocity is v = (68 Hz)(28m) = 1904 m/s.
As with all waves, the relationship between the speed of sound, its frequency, and its wavelength is vw=f, where vw denotes the speed of sound, f denotes its frequency, and f denotes its wavelength.
The frequency of a wave is expressed in Hertz (Hz), which is the number of waves that pass by each second. A sound wave, for instance, might have a frequency of 450 Hz.
"The distance between the two successive crests or troughs of the light wave" is how wavelength of light is described. Using the Greek letter lambda (λ), it is identified.
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Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0∘ west of north. Jane walks 12.0 m in a direction 30.0∘ south of west. They then stop and turn to face each oth
Answer:
a) 24.33 m of distance.
b) 34.55° east of the south.
Explanation:
The question is incomplete. The whole exercise is the following:
"Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0° west of north. Jane walks 12.0 m in a direction 30.0° south of west. They then stop and turn to face each other.
(a) What is the distance between them?
(b) In what direction should Ricardo walk to go directly toward Jane?"
Now that we know what we need to do in this question, let's head for every part of the problem.
a) Distance between Ricardo and Jane
In this case, we need to analyze the given data:
Ricardo (which we will call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 12 m at 30° south of west. So the distance between them, will be the point where they both stop and face each other. This point can be seen in the image attached (See picture).
Let's call the distance between them as "D", to get the distance of D, according to the picture will be:
D = J - R (1)
However, as they are facing in different angles and directions, we cannot do the difference of their values distance just like that. In order to do that, we need to calculate the components in the "x" and "y" axis of each vector. In that way, we can get the components of x and y of the Distance D, and then, the whole distance between them will be:
D = √Dx² + Dy² (2)
So, let's get the components of x and y of R and J.
For Ricardo (R):
Rx = R sin60° = 28 sin60° = -24.25 m
Ry = R cos60° = 28 cos60° = 14 m
The sign "-" it's because R it's on the second quadrant, therefore in x, we'll have to add the negative.
For Jane (J):
Jx = J cos30° = 12 cos30° = -10.39 m
Jy = J sin30° = 12 sin30° = -6 m
Again, the negative is added because J is on the third quadrant.
Now that we have the components, let's calculate vector D using expression (1):
Dx = -10.39 - (-24.25) = 13.86 m
Dy = -6 - 14 = -20 m
Now, using expression (2) we can finally know the distance between Jane And Ricardo:
D = √(-20)² + (13.86)²
D = 24.33 mThis is the distance between Jane and Ricardo.
b) Direction of Ricardo walking to Jane
In this case, we already have the components of x and y of the distance between them, so, to know the direction:
Tanα = Dy/Dx
α = tan⁻¹ (Dy/Dx)
Replacing the values we have:
α = tan⁻¹ (-20/13.86)
α = 55.45°
Which should south of east or:
β = 90 - 55.45
β = 34.55°Ricardo should walk 34.55° east of south
Hope this helps
state three uses of a magnet
Explanation:
Compass. A compass uses a magnet to direct its needle to the north pole
Magnets are used to make a tight seal on the doors to refrigerators and freezers. They power speakers in stereos, earphones, and televisions. Magnets are used to store data in computers, and are important in scanning machines called MRIs.
Answer:
Magnets are used to make a tight seal on the doors to refrigerators and freezers. They power speakers in stereos, earphones, and televisions. Magnets are used to store data in computers, and are important in scanning machines called MRIs (magnetic resonance imagers), which doctors use to look inside people's bodies.
Explanation: