Which conditions contribute to engine deposits
Answers
Driving consistently will cause the oil to heat up and break down to create sludge.
And if oil gets too hot, it will cause metal on metal grinding due to the oil thinning out.
Hope this helps you. :)
Related Questions
2.2.1 A loss-free generator supplies 50 MW to an infinite bus, the steady-
state limit of the system been 100 MW. Determine whether the generator will
remain in synchronism if the prime mover input is abruptly increased by
30 Mw.
Answers
Answer:
Рвоы
Explanation:
Иттің папасы өлңп қалды дейді
what is automechanic
Answers
Answer:
An auto mechanic is a mechanic who services automobiles, sometimes specializing in one or more automobile brands or sometimes working with any brand. In repairing cars, their main role is to diagnose the problem accurately and quickly.
Compute the infiltration rate f and cumulative infiltration F after one hour of infiltration into a silt loam soil that initially had an effective saturation of 30 percent. Assume water is ponded to a small but negligible depth on the surface.
Answers
The problem requires us to calculate the infiltration rate f and cumulative infiltration F after one hour of infiltration into a silt loam soil that initially had an effective saturation of 30 percent. Infiltration is the process through which water enters the soil and replenishes the groundwater table.
Several factors affect infiltration, including the intensity of rainfall, soil properties, land use, land cover, slope, and surface runoff. To calculate the infiltration rate and cumulative infiltration after one hour of infiltration into a silt loam soil, we follow these steps:
Step 1: We determine the initial effective saturation, which is given as 30 percent.
Step 2: The cumulative infiltration is given by the relation: F = ∫fdt, where f is the infiltration rate, and F is the cumulative infiltration.
Step 3: Assuming infiltration occurs at a constant rate, after one hour, the effective saturation becomes 70%. Therefore, the change in effective saturation in one hour is 40%. This implies that the amount of water that infiltrates the soil in one hour is 40% of the soil depth.
Step 4: We calculate the amount of water that infiltrates the soil, which is given as i = (θt2 - θt1)/t, where i is the infiltration rate, θt2 is the final soil moisture content, θt1 is the initial soil moisture content, and t is the duration, which is 1 hour or 60 minutes. Substituting the given values, we obtain i = 0.0067 cm/min.
Step 5: The cumulative infiltration is given as F = f * t. Substituting the calculated values, we get F = 0.0067 * 60 = 0.402 cm.
Therefore, the infiltration rate is 0.0067 cm/min, and the cumulative infiltration is 0.402 cm after one hour of infiltration into a silt loam soil that initially had an effective saturation of 30 percent.
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In how many ways 2450 can be written as a product of 2 factors?
Select one:
O a. 9
O b. 6
C. 18
O d. 10
Answers
Answer:
search up factors of 2450 and divide by two
The number of ways 2450 can be written as a product of 2 factors is 9 ways
How to find factors of numbers?Factors of 2,450 = 1, 2, 5, 7, 10, 14, 25, 35, 49, 50, 70, 98, 175, 245, 350, 490, 1225, 2450
2450 has 18 factors.The number of ways 2450 can be written as a product of 2 factors = number of factors / 2
= 18/2
= 9 wats
This means, taking the product of two factors such as;
1 × 2450
2 × 1225
5 × 490
7 × 350
10 × 245
14 × 175
25 × 98
35 × 70
50 × 98
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Where's an inductor most likely to be found in a power-supply circuit?
Answers
Among tatal plane crashes that occurred during the past 50 years, 104 were due to pilot enor, 93 were due to other human erro, 390 were due to weather, 235 were dus to mechanical problems and 264 were due to sablage D Construct the relative frequency duribution. What is the most serious threat to aviation safety, and can anything be done about a CHILD Complete relative frequency distribution below Cause Relative Frequency Phot smo Other humanoor Methumical.prohiumம் Sabotage Round to one decimal placa as needed)
Answers
Cause Relative Frequency
Pilot error 104 / (104 + 93 + 390 + 235 + 264)
Other human error 93 / (104 + 93 + 390 + 235 + 264)
Weather 390 / (104 + 93 + 390 + 235 + 264)
Mechanical problems 235 / (104 + 93 + 390 + 235 + 264)
Sabotage 264 / (104 + 93 + 390 + 235 + 264)
Now let's calculate the values:
Cause Relative Frequency
Pilot error 104 / 1086 ≈ 0.0957
Other human error 93 / 1086 ≈ 0.0857
Weather 390 / 1086 ≈ 0.3595
Mechanical problems 235 / 1086 ≈ 0.2164
Sabotage 264 / 1086 ≈ 0.2437
To determine the most serious threat to aviation safety, we look for the cause with the highest relative frequency. In this case, the cause with the highest relative frequency is weather, which accounts for approximately 35.95% of the total plane crashes.
Regarding whether anything can be done about weather-related incidents, it's important to note that weather conditions are natural phenomena that can be unpredictable and challenging to control. However, aviation safety measures can be implemented to minimize the risks associated with adverse weather conditions. These measures include advanced weather monitoring systems, improved pilot training for dealing with weather-related challenges, and enhanced aircraft technology designed to withstand severe weather conditions.
Note: The relative frequencies have been rounded to four decimal places for ease of reading.
The relative frequency distribution of the total plane crashes that occurred during the past 50 years can be obtained as follows: Cause Number of Crashes Relative Frequency Pilot error 104 0.106 Other human error 93 0.095 .
Weather 390 0.398 Mechanical problems 235 0.240 Sabotage 264 0.270 Total 1,086 1.109 The most serious threat to aviation safety is weather, which caused 39.8% of all plane crashes. Yes, something can be done to minimize the effect of weather on aviation safety.
The best way to prevent weather-related plane crashes is to gather and disseminate as much information as possible about weather conditions and adjust flight plans and routes accordingly.
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Where is refrigerant added to a low-pressure system during the charging process?
A
The access valve on the purge unit entering the condenser.
B
The lowest access point on the system such as the condenser charging valve.
C
The highest access point on the system such as the evaporator inlet valve.
D
The lowest access point on the system such as the evaporator charging valve.
Answers
Refrigerant is typically added through the lowest access point on the system, which is typically the evaporator charging valve.
Where is refrigerant added to a low-pressure system during the charging process?During the charging process of a low-pressure refrigeration system, refrigerant is typically added through the lowest access point on the system, which is typically the evaporator charging valve.
This valve is located on the suction line close to the evaporator and provides a direct path for refrigerant to enter the system.
Adding refrigerant through this point ensures that the refrigerant is evenly distributed throughout the system and that the evaporator is properly charged.
Adding refrigerant at other access points, such as the condenser charging valve or the evaporator inlet valve, may lead to improper refrigerant distribution and could potentially damage the system.
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1. What are some pendulum wave characteristics?
2. What are waves characteristics?
3. List characteristics that they both share
Answers
Answer:
Explanation:
The saturation of dissolved oxygen concentration of a stream is 9.1 mg,/l.. At a sewage outfall. the dissolved oxygen concentration of the stream is 8.0 mg/L. The stream has a reaeration rate constant of 4 /day and a deoxygenation rate constant of 0.1 /day. initial BOD ultimate in the mixture zone is 200 mg/L. The time after discharge at which the water will reach its minimum dissolved oxygen concentration is :__________
Answers
Question 2
For the circuit above in question 1, what is the most negative value v_{s}v
s
can take
before the amplifier saturates? Express your answer in mV and omit
units from your answer.
Answers
The most negative value can take before the amplifier saturates. Suppose, Consider a non-ideal op amp where the output can saturate. Hence, The most negative value of is 0.5 mV
Can take before the amplifier saturates?The most negative value v2 can take before the amplifier saturates.Suppose, Consider a non-ideal op amp where the output can saturate.The open voltage gain is2*10 4 where,According to figure,
The negative output value is
v0 = -10V
We need to calculate the most negative value of
Using given formula
v0 = -A(Vs)
Where, = output value
A = voltage gain
Put the value into the formula
-10 = -2 *10 4* Vs
vs = 10/2*10 4
Vs = 0.0005v
Vs = 0.5MV
Hence, The most negative value of is 0.5 mV.
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The most negative value can take before the amplifier saturates. Suppose, Consider a non-ideal op amp where the output can saturate. Hence, The most negative value of is 0.5 mV
Can take before the amplifier saturates?The most negative value v2 can take before the amplifier saturates. Suppose, Consider a non-ideal op amp where the output can saturate. open voltage gain is2*10 4 where, According to figure,
The negative output value is
v0 = -10V
We need to calculate the most negative value of
Using given formula
v0 = -A(Vs)
Where, = output value
A = voltage gain
Put the value into the formula
-10 = -2 *10 4* Vs
vs = 10/2*10 4
Vs = 0.0005v
Vs = 0.5MV
Hence, The most negative value of is 0.5 mV.
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how can I skip more helppppppppppppppppppppppp
Answers
Answer: skip what
Explanation:
Answer:
answer someone else's question and you will never have to skip again
Explanation:
Tech a says that only a certain few people will find jobs in the automotive industry. Tech b says the automotive industry offers numerous career choices . Who's correct?
Answers
Answer: Tech B
Explanation:
From the question above, tech B saying the automotive industry offers numerous career choices is the correct answer. Pursuing a career in automotive industry is challenging and rewarding as one works with both vehicles and technology.
Examples of career choices in the automotive industry are car detailer, tire technician, car rental agent, auto mecahnic, vehicle inspector, auto electrician, auto engineer etc.
state the parallelogram law of forces
Answers
Answer:
The law of parallelogram of forces states that if two vectors acting on a particle at the same time be represented in magnitude and direction by the two adjacent sides of a parallelogram drawn from a point their resultant vector is represented in magnitude and direction by the diagonal of the parallelogram drawn from .
The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 x 3^106 Btu/h. The combustion efficiency of the boiler is measured to be 0.7 by a hand-held flue gas analyzer. After tuning up the boiler, the combustion efficiency rises to 0.8. The boiler operates 4200 hours a year intermittently. Taking the unit cost of energy to be $4.35/10^6 Btu, determine the annual energy and cost savings as a result of tuning up the boiler.
Answers
Answer:
Energy Saved = 6.93 x 10⁹ Btu
Cost Saved = $ 30145.5
Explanation:
The energy generated by each boiler can be given by the following formula:
\(Annual\ Energy = (Heat\ In)(Combustion\ Efficiency)(Operating\ Hours)\)
Now, the energy saved by the increase of efficiency through tuning will be the difference between the energy produced before and after tuning:
\(Energy\ Saved = (Heat\ In)(Efficiency\ After\ Tune - Efficiency\ Before\ Tune)(Hours)\)\(Energy\ Saved = (5.5\ x\ 3\ x\ 10^{6}\ Btu/h)(0.8-0.7)(4200\ h)\)
Energy Saved = 6.93 x 10⁹ Btu
Now, for the saved cost:
\(Cost\ Saved = (Energy\ Saved)(Unit\ Cost)\\Cost\ Saved = (6.93\ x\ 10^{9}\ Btu)(\$4.35/10^{6}Btu)\\\)
Cost Saved = $ 30145.5
Who is Mario and Luigi
Answers
Answer:
they are fictional characters featured in video games etc
Answer: Mario and Luigi are game characters, which feature in the Super Mario Maker series, the Paper Mario series, but most notably, the Super Mario Bros. series. Mario debuted in Donkey Kong (1981), while Luigi debuted in Mario Bros (1983, not to be confused with Super Mario Bros, which released two years after Mario Bros).
how can an airplane fly in math form? maybe physics...
Answers
Answer:
the aeroplane can fly throw the petrol and
You were hired to build an artificial reservoir in an area of 50 acres and a depth of 7 feet is required. Calculate the volume in cubic meters
Answers
The volume of the artificial reservoir can be calculated using the formula: Volume = Area x Depth. First, we need to convert the area of 50 acres to square meters. One acre is equal to 4046.86 square meters, so 50 acres is equal to:
50 acres x 4046.86 square meters/acre = 202343 square meters.
To calculate the volume of an object, we need to know its dimensions. In this case, we were given the area (50 acres) and the depth (7 feet) of the artificial reservoir. We used the formula Volume = Area x Depth to find the volume in cubic feet. However, since the final answer is required in cubic meters, we needed to convert the feet to meters using the conversion factor 0.3048 meters/foot.
To calculate the volume of the reservoir, we need to convert the area and depth into meters, then multiply them together.
Convert the area from acres to square meters.
1 acre = 4,046.86 square meters
50 acres = 50 * 4,046.86 = 202,343 square meters
Convert the depth from feet to meters.
1 foot = 0.3048 meters
7 feet = 7 * 0.3048 = 2.1336 meters
Calculate the volume.
Volume = Area * Depth = 202,343 square meters * 2.1336 meters = 89,687.41 cubic meters
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a lowpass filter has the frequency response function as 1. compute the impulse response h(t) of the filter
Answers
h(t) = F^-1{H(f)}
Since H(f) = 1 for all frequencies, we can simply take the inverse Fourier transform of the constant function 1 to obtain the impulse response:
h(t) = F^-1{1}
Using the Fourier transform property that F{1} = delta(f), where delta(f) is the Dirac delta function, we can write:
h(t) = F^-1{1} = F^-1{F{delta(f)}}
Applying the inverse Fourier transform of the Dirac delta function, which is a pulse of unit area centered at t = 0, we obtain:
h(t) = F^-1{F{delta(f)}} = 1/2pi * integral from -infinity to infinity of delta(f) * e^(j2pift) df
The integral evaluates to 1/2pi, since the Dirac delta function integrates to 1 over its support. Therefore, the impulse response of the lowpass filter is:
h(t) = 1/2pi * integral from -infinity to infinity of e^(j2pift) df
The integral evaluates to 2pi * delta(t), where delta(t) is the Dirac delta function. Therefore, the impulse response of the lowpass filter is:
h(t) = 2pi * delta(t)
This result indicates that the impulse response of a lowpass filter with frequency response function H(f) = 1 is a Dirac delta function scaled by a factor of 2pi. This impulse response represents the ideal response of a lowpass filter, which attenuates all high-frequency components of a signal while allowing low-frequency components to pass through.
*sapnap teaching you how to drive*
"Skeppy and Badboyhalo are crossing the street, what do you hit?"
"Skeppy, I would never hurt Bad."
"whA- THE BRAKES YOU HIT THE BREAKS!!"
*Dream wheezing from the back*
Answers
Answer:
yes dream
Explanation:
Answer:
Me: "i would just hit you, sapnap. In the freaking face" LOL
The part of a circuit that carries the flow of electrons is referred to as the?
Conductor
Electrostatic Field
Dieletric
Insulator
Answers
Answer:
Conductor
Explanation:
Current is carried by a conductor.
__
The purpose of a dielectric and/or insulator is to prevent current flow. An electrostatic field may set up the conditions for current flow, but it carries no current itself.
Which type of hybrid vehicle is propelled by only an electric motor and does not require a traditional transmission to drive the wheels
Answers
Answer:
Dual-Mode Hybrid
Explanation:
The type of hybrid vehicle propelled by only an electric motor and does not require a traditional transmission to drive the wheels is known as "DUAL-MODE HYBRID."
Dual-Mode Hybrid is a type of Hybrid Electric Vehicle (HEV) which contains a separate generator consisting of rechargeable batteries. The engine ensures the wheels and the generator are moved; thereby, the electric motor and the batteries are fully powered.
A good example is a Toyota Prius, where during driving conditions, only the electric motor drives the wheels, in which the batteries supply the car with power.
what's the answer???
Answers
Answer:
The best chose will happen to be C
What do we need to build a car?
Answers
Explain what the ancient Romans did to solve the problem in the following scenario.
Situation: In ancient Italy, farmers were experiencing a drought. Rather than move to where the water was, Roman inventors decided to bring the water to the farmers.
Answers
Answer:
They moved fresh water around their vast empire with aqueducts and canals.
Explanation:
The two main types of disc brake calipers are:
a. fixed and free
b. fixed and sliding.
c. free and sliding.
d. fixed and broken
Answers
Answer: b fixed and sliding
Explanation:
A pulse-jet baghouse is desired for a finished cement plant. Calculate the number of bags required to filter 500 m3/min of air with a dust loading of 3.0 g/m3. Each bag is 3.0 m long with a 0.13 m diameter. If the average pressure drop is 1.0 kPa and the main fan is 60% efficient, calculate the fan power in kW. If the pulse air volumetric flow rate is 0.5% of the filter airflow rate and the pulse air pressure is 6.0 atm, calculate the power drawn by a 50% efficient compressor (in kW).
Answers
Answer:
1) 4.41 * 10^-4 kw
2) 2.20 * 10^-4 kw
Explanation:
Given data:
Filter = 500 m^3/min
dust velocity = 3g/m^3
bag ; length = 3 m , diameter = 0.13 m
change in pressure = 1 kPa
efficiency = 60%
1) Calculate the Fan power
First :
Calculate the total dust loading = 3 * 500 = 1500 g
To determine the Fan power we will apply the relation
\(n_{o} = \frac{\frac{p}{eg*Q*h} }{1000}\) = \(\frac{\frac{p}{(3*10^{-3})* 981*( 500/60) *3 } }{1000}\)
fan power ( \(n_{0}\) ) = 4.41 * 10^-4 kw
2) calculate power drawn
change in P = 6 atm = 6 * 10^5 pa
efficiency compressor = 50%
hence power drawn = 4.41 * 10^-4 kw * 50% = 2.20 * 10^-4 kw
Harry is using a backpack to carry all of his interior design supplies. He has his sketchbook, measuring tape, level, colored pencils, and water bottle placed in the main compartment of the bag. What risk is Harry taking by carrying his supplies like this?
A.
His level or sketchbook may mark or destroy his other items
B.
His measuring tape may leak ink on his sketchbook and other items
C.
His water bottle may leak or his colored pencils may mark items
D.
Harry isn’t taking any risk
Answers
What is a collection of configuration settings stored as a text file with an .inf extension?
a. Security template
b. Policy configuration
c. Deployment list
d. None
Answers
Design and implement a circuit that operates as a gated binary counter. when the counter is enabled, it should increment from 000, 001, ..., 111, and finally roll over back to 000 and repeat the sequence. when disabled, the counter should hold its present value. choose the flipflop that allows you to minimize the number of additional gates needed to realize this functionality.
Answers
To design a gated binary counter, we can use a 3-bit binary counter with JK flip-flops and a 2-input AND gate as the gating signal. The AND gate will act as the enable/disable signal for the counter.
The circuit diagram is as follows:
_____ _____ _____
EN | | | | | |
-----| AND |---|J Q|---|J Q|---Q0
_____|_____| |_____| |_____|
| _____ _____
| | | | |
|---------| AND |---|J Q|---Q1
| |_____| |_____|
| _____ _____
| | | | |
|---------| AND |---|J Q|---Q2
|_____| |_____|
The AND gate acts as the enable/disable signal, EN. When EN is high (1), the counter will increment, otherwise, the counter will hold its present value.
The J and K inputs for the flip-flops can be set as follows to achieve binary counting:
Q0: J = K = 0
Q1: J = 0, K = Q0
Q2: J = K = Q0Q1
The output, Vo, will be the binary count represented by the three flip-flops, Q2Q1Q0.
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An AC bridge has 4 arms. In arm AB, a 120 kilo-ohm resistor and a 47 microfarads capacitor are connected in parallel while arm BC has 330 microfarads capacitor. If arm AD has a 330 kilo-ohm resistor, calculate the value of the unknown capacitor and resistor in arm CD connected in series. (AC power is supplied through A and C while the detector is connected across BD)
Answers
The unknown capacitor in arm CD must have a value of 330 microfarads, and the unknown resistor must have a value of 100 kilo-ohms.
To solve the problem, use the following formula:
Cseries = C1 x C2 / (C1 + C2)
Where C1 is the value of the capacitor in arm AB (47 microfarads) and C2 is the value of the capacitor in arm BC (330 microfarads).
Therefore, Cseries = 330 microfarads.
Also, the total resistance of arms CD is the sum of the resistance of the resistor (R) and the reciprocal of the capacitive reactance of the capacitor (1/Xc).
Using the following formula:
Rtotal = R + 1/Xc
Where Xc = 1/2πfC,
f is the frequency and C is the capacitance.
For this problem,
Xc = 1/2π(50)(330 x 10-6)
=> 100 kilo-ohm.
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