which of the following is the statement of dalton's law of partial pressures? multiple choice question. pv

Answers

Answer 1

The statement of dalton's law of partial pressures is the total pressure by a mixture of gases is equal to the sum of the partial pressures of each gas that makes up the mixture. The correct answer is B.

The pressure that each gas would produce if it occupied the same volume of the mixture at the same temperature alone is referred to as the partial pressure.

the law of partial pressure known as Dalton's Law A combination of gases exerts a pressure that is equal to the sum of the pressures that each gas exerts on its own. Each gas exerts pressure directly proportional to the amount of that gas present in the gas mixture.

In closed vessels over water, Dalton found that oxygen interacted with either one or two volumes of nitric oxide. This ground-breaking observation of integral multiple proportions served as crucial experimental support for his fledgling atomic theories.

Your question is incomplete but most probably your full question was

Which of the following is a statement of daltons law of partial pressure

A. The total pressure of a mixture of gases is the product of the partial pressures of each gas in the mixture

B. The total pressure of a mixture of gases is the sum of the partial presaure of each gas that makes up the mixture

C. gases can exist as mixtures at STP only

D. in a mixture of two gases, the pressure of each gas is 1/2 of the total pressure

E. the partial pressure of a gas is equal to the total pressure of the mixture

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Related Questions

If I were to take a ball to the moon, where gravity is 1/6th that on the Earth, what will happen to its GPE if I hold it at the same height both places?
A. 6 times as much
B. Not enough info
C. 1/6th as much
D. Disappear

Answers

Answer:

C. 1/6th as much

Explanation:

The gravitational potential energy (GPE) of an object depends on its mass, the acceleration due to gravity, and its height above a reference point. Since the gravity on the moon is 1/6th that on Earth, the acceleration due to gravity on the moon is 1/6th that on Earth. Therefore, if you hold the ball at the same height on the moon as on Earth, its GPE will be 1/6th as much as it was on Earth. So the answer is C.

Can someone please answer this? I am really lost.

Can someone please answer this? I am really lost.

Answers

Answer:

8.0 rad/s

Explanation:

I₁ = 1.0 kgm², ω₁ = -20.0 rad/s (clockwise is positive direction)

I₂ = 4.0 kgm², ω₂ = 15.0 rad/s

Angular momentum conservation:

I₁ω₁ + I₂ω₂ = (I₁ + I₂)ω

1.0 x (-20.0) + 4.0 * 15.0 = (1.0 + 4.0)ω

40.0 = 5.0ω

so ω = 8.0 rad/s

Cassidy Carver's family child care center has an activities table with four chairs an easel that can accommodate a child on each side, a play kitchen area with room for four children and a building blocks area that can hold three children. How many play spaces are in Carver's environment

cannot determine from information prividrd

thirteen

three

four​

Answers

Answer:4

Explanation:

re testing a new amusement park roller coaster with an empty car with a mass of 100 kg. One part of the track is a vertical loop with a radius of 12.0 m. At the bottom of the loop (point A) the car has a speed of 25.0 m/s and at the top of the loop (point B) it has speed of 8.00 m/s . You may want to review (Pages 203 - 212) . For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A vertical circle with friction. Part A As the car rolls from point A to point B, how much work is done by friction?

Answers

Answer:

-4530 J

Explanation:

Given that

Mass of the car, m = 100 kg

Speed of the car at point A, v1 = 25 m/s

Speed at point B, v2 = 8 m/s

Radius of the track, r = 12 m and with respect to the origin of the center of the track, we say that y1 = -12 at point A and y2 = 12 at point B

We also know that

W(total) = W(grav) + W(other) = K₂ - K₁

Work done by the gravitational force, W(grav) = -U(grav) = mgy1 - mgy2

Kinetic Energy, K = ½mv²

Adding all together, we have

½mv₁² + mgy1 + W(other) = ½mv₂² + mgy2

½ * 100 * 25² + 100 * 9.8 * -12 + W = ½ * 100 * 8² + 100 * 9.8 * 12

50 * 625 + 980 * -12 + W = 50 * 64 + 980 * 12

31250 - 11760 + W = 3200 + 11760

19490 + W = 14960

W = 14960 - 19490

W = -4530 J

Can anyone help with the attached question

Can anyone help with the attached question

Answers

The wave front, also known as the wavefront, is an imaginary surface that represents equivalent points of a wave that vibrate in sync. The correct option is D ; 2.0 .

What is a wavefront in physics?

A wave front is described as a surface where the wave's phase remains constant. At any one time, all particles of the medium are moving in the same direction along a certain wave front. Two kinds of wave fronts are very essential. They are plane and spherical wave fronts, respectively. A wavefront is a surface on which the wave disturbance is in the same phase at all places. For example, the ripples of water created when a stone is tossed into a pond.

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Vector B~ has x, y, and z components of 4.3, 4.5, and 5.1 units, respectively. Calculate the magnitude of B~ .

Answers

The magnitude of vector B is determined as 8.05 units.

What is the magnitude of a vector?

The magnitude of a vector is the scalar value of a vector that can  be used to describe the unit value of the vector.

The magnitude of a vector can also be described as the resultant of the vector because it is usually the single value of the vector that can be used to represent the vector.

The magnitude of vector B is calculated as follows;

|B| = √(x² + y² + z²)

where;

x is the x - component of the vectory is the y - component of the vectorz is the z - component of the vector

|B| = √(4.3² + 4.5² + 5.1²)

|B| = 8.05 units

Thus, we can conclude that vector B with x, y, and z components of 4.3, 4.5, and 5.1 units, respectively, has a magnitude of 8.05 units.

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A 6 cm object is 8 cm from a convex lens that has a focal length of 2.7 cm. The image is 4 cm from the lens. The height of the image is ? cm.

Answers

A 6 cm object is 8 cm from a convex lens that has a focal length of 2.7 cm. The image is 4 cm from the lens. The height of the image is 3 cm

To find the height of the image, we can use the magnification formula:

Magnification (M) = Image height (h') / Object height (h) = Image distance (d') / Object distance (d)

We are given:
- Object height (h) = 6 cm
- Object distance (d) = 8 cm
- Image distance (d') = 4 cm

We need to find the image height (h').

First, let's find the magnification (M) using the formula:

M = d' / d = 4 cm / 8 cm = 0.5

Now, we can find the image height (h'):

h' = M * h = 0.5 * 6 cm = 3 cm

So, the height of the image is 3 cm.

The question was Incomplete, Find the full content below :

A 6 cm object is 8 cm from a convex lens that has a focal length of 2.7 cm. The image is 4 cm from the lens. The height of the image is ___ cm.

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A concept is the general idea of objects, events, animals, or people based on common features, traits, or characteristics.
Please select the best answer from the choices provided
ОТ
OF

Answers

Answer:

True.

Explanation:

Science can be defined as a branch of intellectual and practical study which systematically observe a body of fact in relation to the structure and behavior of non-living and living organisms (animals, plants and humans) in the natural world through experiments.

A concept is the general idea of objects, events, animals, or people based on common features, traits, or characteristics. It is typically considered to be an abstract idea or general notion that is formed by the mental combination of all the characteristics pertaining to the idea.

Generally, concepts are used in the problem-solving process as it serves as a benchmark or yardstick for the solutions. Some examples of concepts in physics are conservation of energy and momentum, electromagnetic waves, heat, motion and forces, electricity and magnetism, gravity, etc.

Answer:

TRUE

Explanation:

edge

A car starts from rest and accelerates at a rate of 5 m/s^2 for 10 seconds. how far does the car travel during this time?
A. 10 sec
B. 12 sec C. 15 sec
D. 18 sec

Answers

The distance that the car travel during each time is:

A. 10 sec = 250 meters.B. 12 sec =  300 meters.C. 15 sec = 375 meters.D. 18 sec = 450 meters.

During this time, the car will travel a total distance of 250 meters.

This can be calculated by using the equation for displacement: displacement = initial velocity x time + 0.5 x acceleration x time^2.

Therefore, the displacement of the car after 10 seconds is:

D= (0 x 10 + 0.5 x 5 x 10^2) = 250 meters.

t= 12 sec

D= (0 x 12 + 0.5 x 5 x 12^2) = 300 meters.

t= 15 sec

D= (0 x 15 + 0.5 x 5 x 15^2) = 375 meters.

t= 18 sec

D= (0 x 18 + 0.5 x 5 x 18^2) = 450 meters.

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A bug starts out at rest, 3 m to the right of the origin. It then starts moving on a trip. After 1 s, the bug is seen at 9 m to the right of the origin, travelling at 5 m/s to the right. After 7 s (from the start of the trip), the bug is seen at 2 m to the left of the origin, travelling at 8 m/s to the right. a.) What is the position vector of the bug 1 s after the start of the trip

Answers

Answer:

       d = 6 i^   m

Explanation:

This is an exercise in kinematics, where the position vector is the displacement of the body from one point to another.

In this case we are told that for t = 0 the worm is at x₀ = 3m and with velocity starts from zero, after t = 1 s it is at x₁ = 9m and with a velocity of

v₁ = 5 m / s

They ask what is the displacement for the time of 1 s

           

               d = x₁ - x₀

               d = 9 -3 m

               d = 6 m

Bold indicates vector, displacement vector is

             d = 6 i ^ m

I drive 5 miles to my home & 5 miles back to school in 30 minutes because I forgot a book.
1. What is my displacement? A. 0 mi B. 5 mi C. 10 mi D. 15 mi E. 20 mi
2. What is my average speed? A. 0 mi/hr B. 10 mi/hr C. 20 mi/hr D. 30 mi/hr E. 40 mi/hr
3. What is my average velocity? A. 0 mi/hr B. 10 mi/hr C. 20 mi/hr D. 30 mi/hr E. 40 mi/hr

Answers

1) The displacement is 0 mi. Option A

2) The average speed is 20 mi/hr. Option C

3) The average velocity is 0 mi/hr. option A

What is the speed?

We know that when we talk about the speed, we would look at the ratio of the average distance to the average time that is taken and this would span the entire journey not only a section of the journey.

We must note that the displacement is a vector quantity and as such, we have to look at the direction of the motion of the object.

Displacement = 5 miles - 5 miles = 0 miles

Average speed = Total distance/ Time = 5 miles + 5 miles/ 0.5 hr = 20 mi/hr

Average velocity = Displacement/Time = 0 miles// 0.5 hr =  0 mi/hr

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A ball rolls horizontally off an incline, at velocity of 8.00m/s l. If the incline is 3.50m above the ground below determine:

a) how long is the projectile in the air?

B) what is the range of the projectile?

C) what is the x-component of velocity at t= 0. 21s

d) y- component of velocity at t-0.21s

e) what is net velocity at t= 0.21s

Answers

Answer:

sadsadasadsdassda

Find the current flowing across the 30 Ohm resistor. I = [?] A
9.0 V 30 Ω 40 Ω 50 Ω 20 Ω 10 Ω​

ANSWERED: 0.143 A

Find the current flowing across the 30 Ohm resistor. I = [?] A9.0 V 30 40 50 20 10 ANSWERED: 0.143 A

Answers

The current flowing over the 30 Ω resistor is 0.4 A.

How to solve

To discover the current streaming over the 30 Ohm resistor, able to apply Ohm's Law, which states that the current (I) is break even with to the voltage (V) partitioned by the resistance (R). In this case, the voltage over the circuit is given as 9.0 V.

To calculate the full resistance of the circuit, we ought to consider the resistors in arrangement and parallel. The resistors with values of 40 Ω and 50 Ω are in serie.

Hence, the sum of their value (R_series )= 40 Ω + 50 Ω = 90 Ω. The 20 Ω and 10 Ω resistors are in parallel, hence, their resistance is represented as (1/R_parallel) = 1/20 Ω + 1/10 Ω = 1/10 Ω. Disentangling this expression gives R_parallel = 6.67 Ω.

Presently, ready to calculate the entire resistance of the circuit. The resistors with values of 30 Ω and 90 Ω (from the arrangement combination) are in parallel, so their identical resistance is given by 1/R_total = 1/30 Ω + 1/90 Ω = 1/22.5 Ω. Rearranging this expression gives R_total = 22.5 Ω.

At last, able to apply Ohm's Law to discover the current over the 30 Ω resistor. I = V / R_total = 9.0 V / 22.5 Ω ≈ 0.4 A.

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A projectile is fired straight up with an initial velocity of 40.0 m/s . Approximately how high will the projectile ?

Answers

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.

Answers

The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.

How to find displacement ratio?

To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:

d = vt + 1/2at²

where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.

Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.

Assume that the time at which they meet is t, then:

d₁ = 1/2 * 2.4t²

And the equation for the displacement of the second body:

d₂ = 1/2 * 4.8t²

If d₁ = d₂

then, 1/2 * 2.4t² = 1/2 * 4.8t²

Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2

So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.

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What is the period of a mass-spring system with the following characteristics?

What is the period of a mass-spring system with the following characteristics?

Answers

the period of a mass-spring system with the  characteristics can be calculated using the formula T = 2π√(m/k), where m is the mass of the object and k is the spring constant. the period of the mass-spring system with the given characteristics is approximately 3.14 seconds.

A mass-spring system has the following characteristics: A spring that is initially stretched or compressed has an oscillatory motion around its equilibrium position. This is referred to as a mass-spring system.The period of the mass-spring system is the time it takes for one complete cycle, including compression and extension. The period is given by the equation

`T = 2π * √(m/k)`,

where T is the period, m is the mass attached to the spring, and k is the spring constant. Let's consider an example to better understand this formula: Suppose a mass of 5 kg is attached to a spring with a spring constant of 20 N/m. What is the period of the system?

T = 2π * √(m/k) = 2π * √(5/20) = 2π * √(1/4) = 2π * (1/2) = π ≈ 3.14s

Therefore, the period of the mass-spring system with the given characteristics is approximately 3.14 seconds.

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The probability of
an electron penetrating barrier of 10 eV is equal to 0.8 %.  If the width of the potential barrier is 0.6
nm, find the energy of the electron.

Answers

The energy of the electron in the given region is 9.38 eV.

The given parameters:

Probability, e = 0.8%Height of barrier, U₀ = 10 eVWidth of the barrier, w = 0.6 nm

What is electron barrier penetration?

When a particle of energy E less than the potential cannot penetrate inside that region.

The exponential factor is calculated as follows;

\(T = e^{-2 \alpha a} \\\\ 0.008 = e^{-2(0.6 \times 10^{-9})\alpha}\\\\ -2(0.6 \times 10^{-9})\alpha = ln(0.008)\\\\ -2(0.6 \times 10^{-9})\alpha = -4.828\\\\ \alpha = \frac{-4.828}{-2(0.6 \times 10^{-9})} \\\\ \alpha = 4.023 \times 10^9\)

The energy of the electron is calculated as follows;

\(\alpha = \sqrt{\frac{2m(U_0 -E)}{h^2} } \\\\ 4.023 \times 10^9 = \sqrt{\frac{2 ( 9.11 \times 10^{-31} kg)(10 \ eV -E) \ \times 1.6\times 10^{-19} \ J/eV}{(1.055 \times 10^{-34} \ J.s)^2 } } \\\\ (4.023 \times 10^9)^2 = \frac{2 ( 9.11 \times 10^{-31} kg)(10 \ eV -E) \ \times 1.6\times 10^{-19} \ J/eV}{(1.055 \times 10^{-34} \ J.s)^2 }\\\\ 2 ( 9.11 \times 10^{-31} )(10 \ eV -E) 1.6\times 10^{-19} = (4.023 \times 10^9)^2 (1.055 \times 10^{-34} \ )^2\\\\ \)

\(10eV - E = \frac{(4.023 \times 10^9)^2\times (1.055 \times 10^{-34} \ )^2}{2 ( 9.11 \times 10^{-31} ) \times 1.6\times 10^{-19}} \\\\ 10eV - E = 0.62 \ eV\\\\ E = 10 \ eV - 0.62\ eV\\\\ E = 9.38 \ eV\)

Thus, the energy of the electron in the given region is 9.38 eV.

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A roller coaster car(m=80kg) on nitro is moving at a speed of 68 m/s as it starts going up to the top of the ride. How high is the ride’s highest point relative to this starting point?

Answers

According to the given statement 11.48 m high is the ride’s highest point relative to this starting point.

What is speed in physics and its unit?

Speed is the rate of change of a distance with respect to time. Time-distance is one of its dimensions. The result is that the basic units of time and distance are added to produce the SI unit of speed. The Si system of speed is therefore the m per second (m/s).

The following data were obtained from the question:

The roller coaster weighs 1200 Kg in mass (m).

Initial velocity (u) = 15 m/s.

Final speed (v) equals 0 m/s (at highest point)

Acceleration due to gravity (g) = 9.8 m/s²

Highest point (h) =?

The roller coaster's highest point can be found as shown in the illustration below:

h = u²/2g

h = 15² / 2 × 9.8

h = 225/19.6

h = 11.48 m

Therefore, the highest point reached by the roller-coaster is 11.48 m.

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A 1400 kg car traveling in the positive direction takes 11.0 seconds to slow from 25.0 meters per second to 12.0 meters per second. What is the average force on the car during this time?

Answers

Answer:

–1652 N. The negative sign indicate that the force is in opposite direction to car.

Explanation:

The following data were obtained from the question:

Mass (m) of car = 1400 kg

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Force (F) applied on the car =?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Acceleration (a) =?

a = (v – u) /t

a = (12 – 25) /11

a = –13/11

a = –1.18 m/s²

Finally, we shall determine the force on the car as follow:

Acceleration (a) = –1.18 m/s²

Mass (m) of car = 1400 kg

Force (F) applied on the car =?

F = ma

F = 1400 × –1.18

F = –1652 N

Thus, the force on the car is –1652 N. The negative sign indicate that the force is in opposite direction to car.

What is the centripetal force for a roller coaster if the mass is 10 kg and the normal force is 25 N?

Answers

Answer:

Fc = 123 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

\( Fnet = Fapp + Fg\)

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

Given the following data;

Normal force = 25N

Mass = 10kg

To find the centripetal force;

From the net force, we have the following formula;

Fc = N + mg

Where;

Fc is the centripetal force.

N is the normal force.

mg is the the weight of the object.

Substituting into the formula, we have;

Fc = 25 + 10(9.8)

Fc = 25 + 98

Fc = 123 Newton

I've got this question, which option is correct?

I've got this question, which option is correct?

Answers

Answer:

option c is the correct one

In an arcade game a 0.097 kg disk is shot
across a frictionless horizontal surface by compressing it against a spring and releasing it.
If the spring has a spring constant of
166 N/m and is compressed from its equilibrium position by 5 cm, find the speed with
which the disk slides across the surface.

Answers

Answer:

Explanation:

Mass of disk = 0.14 kgSpring constant = 155 N/mLength = 4 cmWe need to calculate the speed Using energy conservationWhere, k = spring constantx = compressed lengthm = mass of the discPut the value into the formulaHence, The speed with which the disk slides across the surface is 1.33095 m/s.

The net force acting on Mrs. Cosce 1,500 kg car is 12,000 N. What is the acceration of her car?

Answers

Answer: 8.0 m/s2

Explanation:

F = ma

a = F/m

F = 12,000 N

m = 1,500 kg

a = 12,000 N / 1,500 kg = 8.0 m/s2

Complete the following statement: A collision is elastic if​

Answers

Complete the following statement: A collision is elastic if...

...the total kinetic energy of the system is conserved before and after the collision, and there is no net loss of energy due to deformation or other non-conservative forces. In an elastic collision, the objects involved bounce off each other without any permanent deformation or generation of heat.

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A person standing on the roof of a building drops a 0.125 Kg ball on the ground. A

child on eight floor saw the ball passing with a speed of 33.1 m/s. The first floor of the building

is 12.0 m high and each successive floor is 8.00 m high. Determine the total numbers of floors

in the building. How fast was the ball falling just before it hit the ground? What was its kinetic

energy just before it hit the ground?

Answers

Answer:

V = a t      velocity after time t

t = 33.1 / 9.80 = 3.38 sec   (time ball had been falling)

S = 1/2 a t^2 = 55.9 m

So the ball had been falling  for 7 * 8 = 56 m  

The child was 7 floors from the top

Since he was on the eight floor the floors below him were

7 * 8 + 12 = 68 m     total floors below child

68 + 56 = 124 m      total height of building

Total floors in building = 7 + 7 + 1 = 15 floors

PE at top = KE at bottom

KE = m g h = .125 * 9.80 * 124 = 152 Joules

Please help me out! I will pay real money to whoever solves this

Please help me out! I will pay real money to whoever solves this

Answers

Answer:

I KNOW THE ANSWER IT WILL COST 30$

Explanation:

19. A pitcher throws a baseball toward a batter at 30m/s. The batter swings his
bat and hits the baseball. The baseball flies away in the opposite direction at a
speed of 35m/s. Is there a transfer of energy in this situation? (SC.7.P.11.4)
a) Yes, because both the bat and the ball are moving after the collision.
b) No, because the ball and the bat only touched for a short time.
c) Yes, because the force from the bat changes the motion of the ball

Answers

A pitcher throws a baseball towards a batter at 30m/s. The batter swings his bat and hits the baseball, then there is a transfer of energy in this situation : c) Yes, because the force from the bat changes the motion of the ball.

How is energy transferred from baseball bat to a baseball?

Although baseball may appear hard and solid, it actually behaves much like a rubber ball. In the fraction of a second that ball collides with the swinging bat, ball compresses as the energy of motion goes into deforming the ball and transforms it into an elastic potential energy.

The collision of baseball with bat is elastic and the collision between baseball and glove is nearly inelastic.

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Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)​

Answers

Answer:

Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)​

Explanation:

A race car driver travel 350 ft/s (250mph) for 20 seconds. How far did she travel?

Answers

7000 feet((((((((((((((((((((
7000 I think I’m not sure

According to the graph below, which of the statements about these cars must be true? A) The speed of car C is greater than the speed of car D. B) At time t = 10 s, both cars have the same velocity. C) The cars meet at time t = 10 s. D) Both cars have the same acceleration. E) The magnitude of the acceleration of car C is less than the magnitude of the acceleration of car D.

Answers

According to the graph below, the statements about these cars must be true are :

At time t = 10 s, both cars have the same velocityThe cars meet at time t = 10 s

options B and C are correct

What is velocity?

Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

There are some similarities  between velocity and speed and they include:  

Both are physical quantities, so both can be measured and quantified. Both the terms (speed and velocity) are associated with moving body only; not with static body. Both have same unit of measurement

Velocity (v) is known as a vector quantity that measures displacement (or change in position, Δs) over the change in time.

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The graph is attached below:

According to the graph below, which of the statements about these cars must be true? A) The speed of
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please help, and show work if you can :)) because of the difference in molar masses, any particle of gas a will be moving slower than any particle of gas b at the same temperature. True or False Does development mean progress?" underlined the compound noun in each sentence. large tomatoes are growing in our backyard . oEscribe. Write sentences about Pablo's daily routine using the images and the verbsbelow.6:30 a, m.6:45 a. m.despertarseducharseA las seis y media se despierta.7:00a.m.7.15 d. m.afeitarsecepillarse los dientes7:30 a. mn.vestirsepeinarse WILL GIVE BRAINLIEST!!!Michelle weighs 90 pounds, which is 120% of what she weighed two years ago. How much did she weigh two years ago? A) 108 poundsB) 75 poundsC) 175 poundsD) 88 pounds Please help me as fast as possible! I really need help! Ill mark as brainliest for correct answers. Please help fast please please tanner is discussing her injury with you during recovery. which of her remarks indicate a need for additional education about her injury? 2. Calculate the mean of the followingsample:20, 15, 22, 13, 14, 18, 19, 11, 23, 17Answer choices:16.817.217.6 Spiral Review Complete the table representing a linear function. Exercise 1 Draw two lines under the verb or verb phrase. Write A (active voice) or P (passive voice) over the verb to tell which voice it is.The vote was taken by our chairperson. Write a Java program to implement Depth first search traversalInsert Delete Display the graph and its execution time Hello I need your help Solve for x. (2x+3) (x-6) What can historians learn about the ancient Romans from the maps that the Romans made? which best identifies the symbolism of this event How is the age distribution pattern of the Hawaiian Islands - Emperor Seamount chain explained by the position of the Hawaiian hotspot? Explain using evidence and reasoning. ABC Company supplies replacement ink cartridges for printers. Daily demand for their cartridges averages 50 units, with a standard deviation of 8 units. The holding cost of the cartridge is $5 per unit per year while the ordering cost is $100 per order. Lead time for replenishment orders is 14 days, and the company operates 365 days per year. Use this information to answer the next 8 questions.Suppose the company wants to maintain a 67% service level. How much safety stock would the company need to carry if it uses a Q system? Pick the closest answer. You pay $3 per square foot for carpeting. Which equation can be solved to find theamount you will pay to cover a triangular section of the floor with a base of 2 yards anda height of 5 yards? Required information The following information applies to the questions displayed below.] Tumer, Roth, and Lowe are partners who share income and loss in a 2:3:5 ratio (in percents: Tumer, 20\%; Roth, 30%; and Lowe, 50% ). The partners decide to liquidate the partnership. Immediately before liquidation, the partnership balance sheet shows total assets, \$128,400; total liabilities, \$80,000; Turner, Capital, $2,700; Roth, Capital, $14,100, and Lowe, Capital, $31,600. The liquidation resulted in a loss of $77,400. Required: a. Allocate the loss to the partners. b. Determine how much each partner should contribute to the partnership to cover any remaining capital deficiency.