Answer:
the net charge carried by the particle is -2.35 × 10⁻⁷ C
Explanation:
Given that;
mass m = 1.41 × 10⁻⁶ kg
Magnitude E = 686 N/C
v = 5.93 m/s
A short time after being launched, the particle is 9.89 x 10-3 m below and 0.151 m east of its initial position
consider vertical;
u =0, y = 9.89 × 10⁻³ m, g = a = 9.8 m/s²
Now, from the second equation of motion;
s = ut + 1/2 × at²
so, y = ut + 1/2 × at²
we substitute
9.89 × 10⁻³ = 0×t + (1/2 × 9.8 × t²)
9.89 × 10⁻³ = 4.9t²
t² = 9.89 × 10⁻³ / 4.9
t² = 0.0201836
t = √0.00201836
t = 0.0449 s
Consider horizontal;
u = 5.93 m/s, a = (qE/m) m/s, t = 0.0449 s, x = 0.151 m
also, from the second equation of motion;
s = ut + 1/2 × at²
so
x = ut + 1/2 × (qE/m) × t²
we substitute
0.151 = (5.93 × 0.0449) + (1/2 × ((q×686)/1.41 × 10⁻⁶) × (0.0449 )²
0.151 = 0.266257 + 0.69149143q / 1.41 × 10⁻⁶
0.151 - 0.266257 = 0.69149143q / 1.41 × 10⁻⁶
-0.115257 = 0.69149143q / 1.41 × 10⁻⁶
-0.115257 × 1.41 × 10⁻⁶ = 0.69149143q
0.69149143q = -1.6251237 × 10⁻⁷
q = -1.6251237 × 10⁻⁷ / 0.69149143
q = -2.35 × 10⁻⁷ C
Therefore, the net charge carried by the particle is -2.35 × 10⁻⁷ C
If a snowboarder going over a jump has 45,000 Jof mechanical energy and you know the snowboarder has 30,000 J of kinetic energy, how much potential energy does the snowboarder have?
Answer:
15,000 J of potential energy
Explanation:
Mechanical energy of an object is the sum of its potential energy and kinetic energy.
45,000 = x + 30,000
45,000 - 30,000 = x
x = 15,000
Mark brainliest please!
ME=KE+PE
45000=30000+PE
PE=15000 J
If the error in the angle is 0.50, the error in sin 90o is
At the given erro in angle, the error in the measurement of sin 90 degrees would be 0.001.
Percentage errorThe percentage error of any measurement is obtained from the ratio of the error to the actual measurement.
The error of sin 90 degrees is calculated as follows;
sin 90 = 1
error in measurement = sin(90 - 0.5)
error in measurement = sin(89.5) = 0.999
Error in sin 90 degreesError in sin 90 degrees = 1 - 0.999
Error in sin 90 degrees = 0.001
Thus, at the given erro in angle, the error in sin 90 degrees would be 0.001.
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A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is
(a) 0.5 Wb
(b) 12.5 Wb
(c) zero
(d) 2 Wb
We know
\(\boxed{\sf Magnetic\:flux=\O=BA}\)
\(\\ \qquad\quad\sf{:}\dashrightarrow \O=5(2.5)\)
\(\\ \qquad\quad\sf{:}\dashrightarrow \O=12.5Wb\)
Explanation:
Magnetic flux = L I
= 5(2.5)
= 12.5 Wb
(b) 12.5 Wb
A set of pulleys is used to lift a piano weighing 1,000 newtons. The piano is lifted 3 meters in 120 seconds. How much power was used?
Answer:
25 watts
Explanation:
Power=work/time
work=force x distance
1000 × 3
=3000 Joules
power= 3000/120
=25 watts
If A set of pulleys is used to lift a piano weighing 1,000 newtons. The piano is lifted 3 meters in 120 seconds. Then the power used is equal to 25 watts.
What is power?Power is the rate at which work is done or energy is transferred. It is a physical quantity that measures how quickly energy is used or transformed.
P=W/s
Where W= work done in joules.
s= time in seconds.
Power is typically measured in watts (W), which is equivalent to joules per second (J/s). In simple terms, power can be defined as the amount of work done or energy transferred per unit of time.
Here in the question,
To calculate the power used to lift the piano, we need to use the formula:
Power = Work / Time
The work done in lifting the piano is given by:
Work = Force x Distance
Where
Force = the weight of the piano, which is 1,000 newtons,
Distance = the height to which it is lifted, which is 3 meters.
Then, the work done is:
Work = 1,000 N x 3 m = 3,000 joules
The time taken to lift the piano is 120 seconds.
Now we can substitute these values in the formula for power:
Power = Work / Time
Power = 3,000 joules / 120 seconds
Power = 25 watts
Therefore, the power used to lift the piano is 25 watts.
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Assume that one object collides with a second object that is at rest. In which of the following scenarios would you expect that momentum would not be conserved?
a) When both objects move in the direction of initial motion after colliding.
b) When the objects move in opposite directions after colliding (the second object moves in the direction of initial motion, the first object moves in the reverse direction).
c) When the objects stick together after colliding.
d) When there is an external force (like friction) acting on the objects in the system.
The momemtum is not conserved in scenario d.
What is momentum?Momentum of an object is the product of its mass and velocity.
How to determine In which of the following scenarios would you expect that momentum would not be conserved?To determine in which of the conditions in which momentum is not conserved, we need to know the law of conservation of momentum.
What is the law of conservation of momentum?The law of conservation of momentum states that as long as no external force acts on a system, the total momentum of the system of two colliding objects is conserved.
If we consider scenarios a, b and c, we see that no external force acts on the system of two objects in the three instances so, the total momentum is conserved.
In scenario d, an external force acts on the system, so total momentum is not conserved since according to the law of conservation of momentum, total momentum is only conserved when there is no external force acting on a system.
So, the momemtum is not conserved in scenario d.
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What conversion takes place in a motor?
A. An electric current into a magnetic field
B. Mechanical energy into electric energy
C. Electric energy into mechanical energy
D. A lower voltage into a higher voltage
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represent the reading of a vernier caliper with a diagram showing the reading 45.75mm
The reading on a vernier caliper can be represented as 45.75mm.
1. Understand the components of a vernier caliper: A vernier caliper consists of two main scales - the main scale and the vernier scale. The main scale is typically graduated in millimeters, while the vernier scale is a smaller scale that slides along the main scale.
2. Locate the main scale: Identify the main scale on the vernier caliper. The main scale is usually marked on the fixed jaw of the caliper and extends in a linear fashion.
3. Identify the vernier scale: The vernier scale is attached to the movable jaw of the caliper. It slides along the main scale and consists of smaller divisions.
4. Align the zero marks: Close the jaws of the caliper and ensure that the zero marks on both the main and vernier scales are aligned.
5. Determine the main scale reading: Read the main scale value that aligns with the zero mark on the vernier scale. In this case, the main scale reading will be 45mm.
6. Locate the vernier scale reading: Examine the vernier scale and identify the division on the vernier scale that lines up perfectly with a division on the main scale. This will give you the additional measurement beyond the main scale reading.
7. Determine the vernier scale reading: Find the division on the vernier scale that aligns with a division on the main scale. The value of this vernier division corresponds to the additional measurement. In this case, the vernier scale reading will be 0.75mm.
8. Add the main scale and vernier scale readings: Combine the main scale reading and the vernier scale reading to get the final measurement. In this case, the final reading will be 45.75mm.
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I need help with this question
Explanation:
a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed
Two small plastic spheres are given positive electric charges. When they are 15 cm apart the repulsive force between them has magnitude 0.22 N. What is the charge on each sphere?
The charge on each sphere is 742 n
What is Charge?In physics, Charge, also known as electric charge is a electrical charge, or electrostatic charge and symbolized q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.
According to the question,
Distance = 15cm or 0.15m
Force = 0.22N
\(K=9*10^{9} kgm^2/c^2\) ( this is a constant value of K)
By using the formula,
F = \(\frac{kQq}{d^{2} }\)
0.220 N = 8.99
N·m²/C² * Q² / (0.15m)²
Q = 7.42e-7
C = 742 n
C is the charge of each sphere .
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A cat pushes a porcelain statue off a bookshelf with a speed of 0.5 m/s and it smashed on the floor 0.85 sec later.
Answer:
167?
Explanation:
i added both
Name as many Greek Gods and Goddesses as you can. What do you know about them?
Answer:
Zeus, Poseidon, Hera, Aphrodite, Ares, Hades
Explanation:
Zeus is the king of gods. Poseidon is god of the sea. Hera is goddess of Marriage, Ares is god of war. Hades god/lord or the underworld.
when the mass of an object increases, the forcé of gravity
Answer:
increace
Explanation:
they are both going up
"n 25 kg object is moving at a velocity or 10 ml. the obec has energy. Calculate it.
The energy of 25 kg object is moving at a velocity or 10 ml is 1250J.
What does a 25 kilogram object travelling at 10 m/s kinetic energy look like?KE = 1/2mv²
The mass is m = 25kg
The velocity is v = 10ms⁻¹
KE = 1/2 × 25 × 10²
⇒ KE = 1250J
Hence, Kinetic energy is 1250J
What is Kinetic energy?The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.
What is velocity?The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
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Which shows evidence of active transport?
A scientist places four identical cells into four different
liquids, each with different concentrations of magnesiuni.
Celll
w
Description of Liquid
Slightly more magnesium than the
cell
The least amount of magnesium
O
O
O
O
cells W and Z
cell W only
cell Y only
cells X and Y
Result
Took in
magnesium
Took in
magnesium
Took in
magnesium
Took in
magnesium
Slightly less magnesium than the
cell
The most amount of magnesium
Answer: D
X and Y
Explanation:
X The least amount of magnesium Took in magnesium
Y Slightly less magnesium than the cell Took in magnesium
Because active transport occurs when ions or molecules move from less concentration region to high concentration region through semi membrane with the help of some energy.
Answer:
Cells X and Y
Explanation:
Active transport occurs when a substance moves across a membrane against its concentration gradient.
Cells W and Z were placed in a liquid containing more magnesium than the cells. Magnesium therefore, diffuses passively down it's concentration gradient into the cells.
However, cells X and Y were placed in a solution containing less magnesium than the cells, yet these cells took in magnesium against this concentration gradient. This, shows that active transport had taken place.
A theme park creates a new kind of water wave pool with large waves caused by constructive interference. There are two wave generators in phase with each other along either side of a pool that is 24.0 m wide. A swimmer that is 9.0 m from one generator and 14.0 m from the other notices that she is in a region with almost no wave amplitude, but there are large-amplitude waves on either side of her.
What is the longest wavelength that will produce this interference pattern?
Express your answer to three significant figures and include appropriate units.
Answer:
10.0 m
Explanation:
Since there is no amplitude at the point of the swimmer, we have destructive interference.
So, the path difference ΔL = L₂ - L₁ where L₁ = swimmer's shorter distance from one generator = 9.0 m and L₂ = swimmer's longer distance from the other generator = 14.0 m. ΔL = 14.0 m - 9.0 m = 5.0 m
Also, since we have destructive interference, ΔL = (n + 1/2)λ where n = number of wavelengths and λ = wavelength of waves
For maximum wavelength, n = 0
So, ΔL = (n + 1/2)λ
ΔL = (0 + 1/2)λ
ΔL = λ/2
λ/2 = ΔL
λ = 2ΔL
λ = 2 × 5.0 m
λ = 10.0 m
So, the longest wavelength that will produce this interference pattern is λ = 10.0 m
4.
a) A loaded box car has a total mass of 6.80 x 10 kg. If the train is travelling at a speed
of 23.7 m/s, what is the mechanical kinetic energy of the box car?
b) If a family car has a mass of 1237 kg, how fast would it have to go to have the same
mechanical kinetic energy as the box car in part a)?
GIVING BRAINLIEST
Mechanical kinetic energy is the energy of an object due to its motion.
a) Mechanical kinetic energy = (1/2)*mass*(velocity)^2
Mechanical kinetic energy = (1/2)*(6.80 x 10^3 kg)*(23.7 m/s)^2
Mechanical kinetic energy = 3.27 x 10^7 J
b) The mechanical kinetic energy of a moving object can be calculated using the following formula:
KE = 0.5 * m * v²,
where m is the mass of the object and v is the velocity.
In this case, we know the mass of the family car (1237 kg) and the mechanical kinetic energy of the box car (50444 J). To calculate the speed of the family car, we can rearrange the formula to solve for v:
v = √(2*KE/m)
v = √(2*50444/1237)
v = 42.62 m/s
What is Mechanical kinetic energy?
Mechanical kinetic energy is the energy associated with the movement of a body or object. It is also known as the energy of motion and is equal to one half of the mass of the object multiplied by the square of its velocity.
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At t=0 a grinding wheel has an angular velocity of 25.0 rad/s. It has a constant angular acceleration of 26.0 rad/s2 until a circuit breaker trips at time t = 2.40 s. From then on, it turns through an angle 435 rad as it coasts to a stop at constant angular acceleration. Part APart complete Through what total angle did the wheel turn between t=0 and the time it stopped? Express your answer in radians. θ = 570 rad Previous Answers Correct Part B At what time did it stop? Express your answer in seconds. t = nothing s Request Answer Part C What was its acceleration as it slowed down? Express your answer in radians per second squared.
Answer:
a) The total angle of the grinding wheel is 569.88 radians, b) The grinding wheel stop at t = 12.354 seconds, c) The deceleration experimented by the grinding wheel was 8.780 radians per square second.
Explanation:
Since the grinding wheel accelerates and decelerates at constant rate, motion can be represented by the following kinematic equations:
\(\theta = \theta_{o} + \omega_{o}\cdot t + \frac{1}{2}\cdot \alpha \cdot t^{2}\)
\(\omega = \omega_{o} + \alpha \cdot t\)
\(\omega^{2} = \omega_{o}^{2} + 2 \cdot \alpha \cdot (\theta-\theta_{o})\)
Where:
\(\theta_{o}\), \(\theta\) - Initial and final angular position, measured in radians.
\(\omega_{o}\), \(\omega\) - Initial and final angular speed, measured in radians per second.
\(\alpha\) - Angular acceleration, measured in radians per square second.
\(t\) - Time, measured in seconds.
Likewise, the grinding wheel experiments two different regimes:
1) The grinding wheel accelerates during 2.40 seconds.
2) The grinding wheel decelerates until rest is reached.
a) The change in angular position during the Acceleration Stage can be obtained of the following expression:
\(\theta - \theta_{o} = \omega_{o}\cdot t + \frac{1}{2}\cdot \alpha \cdot t^{2}\)
If \(\omega_{o} = 25\,\frac{rad}{s}\), \(t = 2.40\,s\) and \(\alpha = 26\,\frac{rad}{s^{2}}\), then:
\(\theta-\theta_{o} = \left(25\,\frac{rad}{s} \right)\cdot (2.40\,s) + \frac{1}{2}\cdot \left(26\,\frac{rad}{s^{2}} \right)\cdot (2.40\,s)^{2}\)
\(\theta-\theta_{o} = 134.88\,rad\)
The final angular angular speed can be found by the equation:
\(\omega = \omega_{o} + \alpha \cdot t\)
If \(\omega_{o} = 25\,\frac{rad}{s}\), \(t = 2.40\,s\) and \(\alpha = 26\,\frac{rad}{s^{2}}\), then:
\(\omega = 25\,\frac{rad}{s} + \left(26\,\frac{rad}{s^{2}} \right)\cdot (2.40\,s)\)
\(\omega = 87.4\,\frac{rad}{s}\)
The total angle that grinding wheel did from t = 0 s and the time it stopped is:
\(\Delta \theta = 134.88\,rad + 435\,rad\)
\(\Delta \theta = 569.88\,rad\)
The total angle of the grinding wheel is 569.88 radians.
b) Before finding the instant when the grinding wheel stops, it is needed to find the value of angular deceleration, which can be determined from the following kinematic expression:
\(\omega^{2} = \omega_{o}^{2} + 2 \cdot \alpha \cdot (\theta-\theta_{o})\)
The angular acceleration is now cleared:
\(\alpha = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot (\theta-\theta_{o})}\)
Given that \(\omega_{o} = 87.4\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(\theta-\theta_{o} = 435\,rad\), the angular deceleration is:
\(\alpha = \frac{ \left(0\,\frac{rad}{s}\right)^{2}-\left(87.4\,\frac{rad}{s} \right)^{2}}{2\cdot \left(435\,rad\right)}\)
\(\alpha = -8.780\,\frac{rad}{s^{2}}\)
Now, the time interval of the Deceleration Phase is obtained from this formula:
\(\omega = \omega_{o} + \alpha \cdot t\)
\(t = \frac{\omega - \omega_{o}}{\alpha}\)
If \(\omega_{o} = 87.4\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(\alpha = -8.780\,\frac{rad}{s^{2}}\), the time interval is:
\(t = \frac{0\,\frac{rad}{s} - 87.4\,\frac{rad}{s} }{-8.780\,\frac{rad}{s^{2}} }\)
\(t = 9.954\,s\)
The total time needed for the grinding wheel before stopping is:
\(t_{T} = 2.40\,s + 9.954\,s\)
\(t_{T} = 12.354\,s\)
The grinding wheel stop at t = 12.354 seconds.
c) The deceleration experimented by the grinding wheel was 8.780 radians per square second.
The equipotential surfaces associated with a point charge are
The equipotential surfaces associated with a point charge are concentric shells.
What is an electric charge?Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge.
The equipotential surface is the region where all points with the same potential are located. On the equipotential surface, a charge can be moved from one point to another without exerting any effort.
Thus,a point charge's related equipotential surfaces are concentric shells.
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Hello! Would like some help on this one, thank you!
Given:
Distance = 130 meters
θ = 35 degrees
F = 40 N
Let's find the work done if the traveler moves 130 meters.
Let's first make a free body sketch:
To find the work done by the traveler over the 130 meters, we have:
\(W=(Fcos\theta)x\)Where:
• W is the work done
,• F is the force applied
,• θ is the angle.
,• x is the distance
Thus, we have:
\(\begin{gathered} W=(40cos35)*130 \\ \\ W=32.766*130 \\ \\ W=4259.59\approx4260\text{ Nm} \end{gathered}\)Therefore, the work done is 4260 Nm.
• ANSWER:
4260 Nm.
Write a haiku
poem
explaining
why graphing
is useful.
If you are
able, share
your poem
with others.
Answer:
Explanation:
graphing is helpful
helps visualize the line
of your equation
A man weighing 720 N and a woman weighing 500 N have the same momentum. What is the ratio of the man's kinetic energy Km to that of the woman Kw?
Answer:
Because weight W = M g, the ratio of weights equals the ratio of masses.
(M_m g)/ (M_w g) = [ (p^2 Man )/ (2 K_man)] / [ (p^2 Woman )/ (2 K_woman)
but p's are equal, so
K_m/K_m = (M_w g)/(M_m g) = W_woman / W_man = 450/680 = 0.662Explanation:
A string with a length of 6.2 m is vibrated at its natural frequency (first harmonic). What is the wavelength of the produced standing wave?
3.1 m
6.2 m
12.4 m
18.6 m
Answer:
12.4m
Explanation:
Given
Length of string = 6.2m
L = λ/2 (for natural frequency (first harmonic)
λ = 2L
λ = 2(6.2)
λ = 12.4m
Hence the wavelength of the produced standing wave is 12.4m
Help please!
How can you differentiate someone who has quality hypnosis training and someone who does not?
The Hypnotic Induction Profile (HIP) or the eye roll test, first proposed by Herbert Spiegel, is a simple test to loosely determine if a person is susceptible to hypnosis. A person is asked to roll their eyes upward. The degree to which the iris and cornea are seen is measured.
What is Hypnotic Induction Profile (HIP)?The Hypnotic Induction Profile (HIP) was created as a quick yet comprehensive evaluation of a person's trait hypnotizability and capacity to enter a hypnotic state.An invitation to enter hypnosis is known as a hypnotic induction, and it usually includes instructions and recommendations to make the subject more receptive to hypnosis. Instructions for relaxation are frequently included in the hypnotic induction, but while nice, they are not always necessary.Do I Have a Receptive Mind? Highly hypnotizable individuals frequently have vivid imaginations and can visualize objects clearly in their minds' eye.When they are reading or watching a movie they enjoy, they frequently lose track of time.To learn more about Hypnotic Induction Profile (HIP) refer to:
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Liquid water is nearly 1,000 times denser than air. Thus, for every 32.0 feet (9.75 m) a scuba diver descends below the water's surface, the pressure increases by 1.00 atm. Human lungs have a volume of approximately 3.50 L. If a scuba diver descends to a depth of 80.0 feet where the pressure is 3.50 atm (2.50 atm from the water and 1.00 atm from the air pressure), then by how much does the volume of a 3.50 L surface sample of air decrease
Answer:
ΔV = -2.1 L
Explanation:
To solve this exercise we can use the ideal gas equation for two points
PV = nRT
P₁V₁ = P₂ V₂
where point 1 is on the surface and point 2 is at the desired depth,
V₂ = \(\frac{P_1}{P_2} \ V_1\)
let's calculate
V₂ = ( \(\frac{1 atm}{2.5 atm}\) ) 3.5 L
V₂ = 1.4 L
this is the new volume, the change in volume is
ΔV = V₂ -V₁
ΔV = 1.4-3.5
ΔV = -2.1 L
1. In Newton’s ring experiment, the diameter of the 5th ring is 0.30 cm and diameter of 15th the ring is 0.62 cm. Find the diameter of the 25th ring.
Answer:
Diameter of Newton’s 5th ring = 0.30 cm
Diameter of Newton’s 15th ring = 0.62 cm
Diameter of Newton’s 25th ring = ?
From Newton’s rings experiment we infer that
D2n+m − D2n = 4λmR
For the 5th and 15th rings we have
D215 − D25 = 4λ * 10 * R _______ (1) (m = 10)
For 15th and 25th rings
D225 − D215 = 4λ * 10 * R _______ (2) (m = 10)
We equate the two derivatives
Equation (2) = Equation (1)
D225 − D215 = D215 − D25
D225 = 2D215 – D25
Substituting the values into the equation
D225 = 2 * 0.62 * 0.62 – 0.3 * 0.3 =0.6788 cm2
D25 = 0.8239 cm
Diameter of \(25^{th}\) Newton Ring = 0.97 cm
Newton Rings is an experiment based on principle of thin film interference
In Newton Rings Experiment the Diameter of \(n^{th}\) dark ring is given by equation (1)
\(\rm D_n= 2\sqrt{n\lambda R} ......(1)\\where \; \\D_n = Diameter\; of \; n^{th} \; dark \; ring }\\n = Number \; of \; Ring\\\lambda = Wavelength \\R = Radius \; of \; Curvature \; of\; the \; lens\)
From the condition given
\(\rm D_5 = 0.3 \; cm \\D_{15} = 0.62 \; cm\\\\D_{25} = To \; be \; determined \\\)
Putting the values in equation (1) for fifth diameter we get
\(\rm D_5 = 0.3=2\sqrt{5\lambda R}.......(2) \\D_{15} = 0.62 = 2\sqrt{15\lambda R}.......(3) \\\\Equation \; (3) - Equation (2) \\\\0.32 = 2\sqrt{\lambda R} ( \sqrt{15} -\sqrt{5})\\\\2\sqrt{\lambda R } = 0.1954....(4)\\\)
So From equation (1) and (4)
\(\rm Diameter \; of \; 25^{th} Ring =D_{25} = 2\sqrt{\lambda R } \times \sqrt{25} \\\\D_{25} = 0.1954\times 5 \\\\D_{25} = 0.97 \; cm\)
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what are beats
a. periodic fluctuations in the velocity of sound waves
b. periodic fluctuations in the wavelength of sound waves
c. periodic fluctuations in the intensity of sound waves
d. periodic fluctuations in the frequency of sound waves
Beats can be defined as the periodic fluctuations in the frequency of sound waves. That is option D
What are sound waves?Sound waves are those waves that are produced by the vibration of an object whose energy is usually propagated through a medium.
When two sound waves of different frequencies meets, a periodic variation that occurs is called beats.
Therefore, Beats can be defined as the periodic fluctuations in the frequency of sound waves.
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Which of the following describes the products of a chemical reaction? A. The original materials B. The substances that are changed O C. The chemicals on the right side of a chemical equation D. The chemicals on the left side of a chemical equation
The products of a chemical reaction are the substances that are changed and the chemicals on the right side of a chemical equation. The correct options are B and C.
What is chemical reaction?The chemical reaction is the reaction between two reactants which led to the formation of products.
The products are substances which forms after reaction. The reactants are the substances which are original materials.
The reactants lie on the left side and products lie on the right side of the reaction.
Thus, the correct options are B and C.
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If the speed of a wave is 330m/s and the period of a wave is 0.0006s what is the wavelength?
Answer:
0.198m
Explanation:
see picture for full solution
a 50 kg boy runs at 3 m/s. how much momentum does he have
Answer:
150 kg-m/s
Explanation:
momentum = m * v
50 * 3 = 150
Which reaction is mainly responsible for the cause of energy radiation from the sun?
Nuclear fusion reaction is mainly responsible for the cause of energy radiation from the sun.
Solar energy is created due to this nuclear fusion. The discharge of energy in the sun is 10²⁶ joules per second
There is nuclear fusion of hydrogen into helium molecules.
Takes place in solar nucleus/plasma, because this reaction can occur only in high temperature.
The special type of fusion that take place in sun is proton-proton fusion.
This kind of fusion is responsible for the cause of energy radiance and is a very efficient method of producing energy.
The 2 condition which help H-H atoms come together is large mass of the sun and the force of gravity.
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