Suppose a utility charges its large industrial customers $0.08/kWh for energy plus $10/mo per peak kVA (demand charge). Peak kVA means the highest level drawn by the load during the month. If a customer uses an average of 750 kVA during a 720-h month, with a 1000-kVA peak, what would be their monthly bill if their power factor (PF) is 0.8

Therefore, of the three options given, the electromagnet with more coils around the metal rod is the most powerful if all other factors such as current and core material are kept constant.

What is the very short response to an electromagnet?

An electromagnet is a temporary magnet made by winding a wire around an iron core. When current flows through the coil, iron becomes a magnet, and when the current is cut off, it loses its magnetic properties.

What is Electromagnetism?

Electromagnetism is the branch of physics that deals with the electromagnetic forces that occur between charged particles. Electromagnetic force is one of the four basic forces and describes the electromagnetic field.

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Answer: The answer is B

Explanation:

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

Answer:

I think Albert Einstein invented physics.

Explanation:

Iam soory if Iam wrong.

Answer:

software calculator is a calculator that has been implemented as a computer program, rather than as a physical hardware device. They are among the simpler interactive software tools, and, as such, they: Provide operations for the user to select one at a time.

Answer: The calculator is a compact portable device that performs mathematical calculations. Some calculators also allow easy text editing and programming. It's also a programming software that simulates a portable calculator. Calculator applications help you make basic math calculations without leaving your screen.

The change in momentum of the ball is -1.215 kg m/s. This is known as the law of conservation of momentum, which states that the total momentum of an isolated system remains constant if no external forces act upon it.

What is Momentum?

Momentum is a physics concept that describes the quantity of motion an object has. It is defined as the product of an object's mass and velocity. The formula for momentum is p = mv, where p is momentum, m is mass, and v is velocity. Momentum is a vector quantity, meaning it has both magnitude and direction. In the absence of external forces, the total momentum of a system is conserved.

a. The initial momentum of the ball can be calculated using the formula:

p = mv

where p is the momentum, m is the mass, and v is the velocity.

p = (0.045 kg) (27 m/s) = 1.215 kg m/s

Therefore, the initial momentum of the ball is 1.215 kg m/s.

b. The final momentum of the ball can also be calculated using the formula:

p = mv

Assuming the ball comes to a stop after being hit, the final velocity will be 0 m/s. So we get:

p = (0.045 kg) (0 m/s) = 0

Therefore, the final momentum of the ball is 0 kg m/s.

c. The change in momentum of the ball can be calculated using the formula:

Δp = pf - pi

where Δp is the change in momentum, pf is the final momentum, and pi is the initial momentum.

Δp = 0 - 1.215 kg m/s = -1.215 kg m/s

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a) The capacitance of the ceramic capacitor is approximately 354.16 pF.

b) The potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

To calculate the capacitance of the ceramic capacitor, we can use the formula:

C = (ε₀ * εᵣ * A) / d

where:

C is the capacitance,

ε₀ is the vacuum permittivity (approximately 8.854 x 10^(-12) F/m),

εᵣ is the relative permittivity of the ceramic (given as 100),

A is the effective plate area (given as 4 cm², which is equal to 4 x 10^(-4) m²),

d is the separation between the plates (given as 0.1 mm, which is equal to 0.1 x 10^(-3) m).

Let's calculate the capacitance in picofarads (pF):

a) Calculation of capacitance (C):

C = (ε₀ * εᵣ * A) / d

= (8.854 x 10^(-12) F/m * 100 * 4 x 10^(-4) m²) / (0.1 x 10^(-3) m)

= (8.854 x 100 x 4) / 0.1

= 354.16 pF

Therefore, the capacitance of the ceramic capacitor is approximately 354.16 pF.

b) To find the potential difference (PD) between the plates when the capacitor is given a charge of 1.2 μC (microcoulombs), we can use the formula:

PD = Q / C

where:

PD is the potential difference,

Q is the charge (given as 1.2 μC, which is equal to 1.2 x 10^(-6) C),

C is the capacitance (calculated in part a) as 354.16 pF, which is equal to 354.16 x 10^(-12) F).

Let's calculate the potential difference (PD):

b) Calculation of potential difference (PD):

PD = Q / C

= (1.2 x 10^(-6) C) / (354.16 x 10^(-12) F)

= 3.39 x 10^6 V

Therefore, the potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

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Answer:

Earth Day is observed globally

Explanation:

The battery would have to supply 7.00 μC of charge to the capacitor.

The energy stored in the capacitor in this case is 7.98 μJ.

The battery would have to supply 4.05 mC of charge to store 1.30 J of energy in the capacitor.

The potential difference across the capacitor would be 20.2 V.

The charge supplied by the battery can be calculated using the formula Q = CV,

where Q is the charge, C is the capacitance, and V is the potential difference.

Thus,

Q = (5.00 μF)(1.40 V)

Q = 7.00 μC.

The energy stored in a capacitor can be calculated using the formula:

E = 1/2 CV^2,

where E is the energy, C is the capacitance, and V is the potential difference.

Thus,

E = 1/2 (5.00 μF)(1.40 V)^2

E = 7.98 μJ.

The charge required to store a certain amount of energy in a capacitor can be calculated using the formula:

Q = √(2CE),

where Q is the charge, C is the capacitance, and E is the energy.

Thus,

Q = √(2(5.00 μF)(1.30 J))

Q  = 4.05 mC.

The potential difference across a capacitor can be calculated using the formula V = √(2E/C), where V is the potential difference, C is the capacitance, and E is the energy.

Thus, V = √(2(1.30 J)/(5.00 μF))

V = 20.2 V

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Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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The angle of projection given that the range is 256√3 m and the maximum height reached is 64 m is 30°

R = u²Sine(2θ) / g

256√3 = u²Sine(2θ) / 9.8

Cross multiply

256√3 × 9.8 = u²Sine(2θ)

Divide both sides by Sine(2θ)

u² = 256√3 × 9.8 / Sine(2θ)

H = u²Sine²θ / 2g

64 = [256√3 × 9.8 / Sine(2θ)] × [Sine²θ / 2 × 9.8]

64 = [256√3 / Sine(2θ)] × [Sine²θ / 2]

Recall

Sine²θ = SineθSineθ

Sine2θ = 2SineθCosθ

Thus,

64 = [256√3 / 2SineθCosθ] × [SineθSineθ / 2]

64 = 256√3 × Sineθ / 4Cosθ

Recall

Sineθ / Cosθ = Tanθ

Thus,

64 = 256√3 / 4 × Tanθ

Divide both side by 256√3 / 4

Tanθ = 64 ÷ 256√3 / 4

Tanθ = 0.5774

Take the inverse of Tan

θ = Tan⁻¹ 0.5774

θ = 30°

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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The well that will have most of the water will be well A.

The underground water supply is defined as a type of water that exists underground in saturated zones beneath the land surface.

From the two wells represented in the diagrams above, Well A has water supply from underground which is lacking in well B.

Therefore, well A will have most of the water more than B.

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Elastic potential energy of spring is twice the gravitational potential energy of the object.

Height of the object, h = 0.5 m

Displacement of the spring, x = 0.5 m

Given that,

Potential energy of the object = Elastic potential energy of spring

mgh = 1/2 kx² = E

When the distance and height are doubled,

GPE = 2 mgh = 2E

Elastic PE = 1/2 k(2x)²

Elastic PE = 4 x 1/2 kx² = 4E

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Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

When the segment is shrunk to one-third of its original length, the ratio of the final linear charge density (?f) to the initial linear charge density (?i) is f/?i = 3

This is because the charge is the same, but the length of the segment has decreased to one-third of its original length. Therefore, the charge density has increased by a factor of 3.

The ratio of the electric force on the proton after the segment is shrunk (Ff) to the force before the segment was shrunk (Fi) is also 3. This is because the electric force is directly proportional to the charge density, so if the charge density increases by a factor of 3, the electric force will also increase by a factor of 3.

If the original segment of wire is stretched to 15 times its original length, the charge density will decrease by a factor of 15. To keep the linear charge density unchanged, we need to add 14 times the original charge to the wire. This is because the original charge will be spread out over 15 times the original length, so we need to add 14 times the original charge to make up for the decrease in charge density.

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Answer:

24.4

Explanation:

you would add all the numbers , 25.5+24.4+24.2= 73.1/3=24.36 and you round up you get 24.4

Answer:

m = \(\frac{k}{g}\) x,

graph of x vs m

Explanation:

For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation

              F_e -W = 0

              k x = m g

              m = \(\frac{k}{g}\) x

We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.

  In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass

Answer:

0.32 m/s^2

Explanation:

v^2-u^2=2as

(6.9)^2-0=2a(72.8)

47.61=a×145.6

a=47.61/145.6

a=0.32 m/ s^2

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

The following explanatory section gives an explanation of this question.

Explanation:

Answer:

65.87 s

Explanation:

For the first time,

Applying

v² = u²+2as.............. Equation 1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance

From the question,

Given:  u = 0 m/s (from rest), a = 1.99 m/s², s = 60 m

Substitute these values into equation 1

v² = 0²+2(1.99)(60)

v² = 238.8

v = √238.8

v = 15.45 m/s

Therefore, time taken for the first 60 m is

t = (v-u)/a............ Equation 2

t = (15.45-0)/1.99

t = 7.77 s

For the final 40 meter,

t = (v-u)/a

Given: v = 0 m/s(decelerates), u = 15.45 m/s, a = -0.266 m/s²

Substitute into the equation above

t = (0-15.45)/-0.266

t = 58.1 seconds

Hence total time taken to cover the distance

T = 7.77+58.1

T = 65.87 s

Answer:

θ = cos^(-1) (-A/B)

Explanation:

The image of the reauktant forces A & B are missing, so i have attached it.

Now, from the attached image, we will see that;

Angle between A and B is θ

Also;

A = Bcos(180° − θ)

Now, in trigonometry, we know that;

cos(180° − θ) = -cosθ

Thus;

A = -Bcosθ

cosθ = -A/B

Thus;

θ = cos^(-1) (-A/B)

Answer:

The current I1 through the resistor R1 is:

I1 = (E1 - E2) / (R1 + R2 + R3 + R4 + R5 + R6 + R7 + R8 + R9)

  = (3 - 6) / (22 + 33 + 1.1 + 3.3 + 33 + 11 + 33 + 1.1 + 3.3)

  = -3 / 116.8

  = -0.02563 A

Explanation:

Answer:

3.34x10*5

Explanation:

this is just a example.

take 3 sig.fig

Answer:

The answer to your problem is, 46.75 degree Celsius

Explanation:

Let l = 10m = 1000 cm

l = 0.5 cm

t1 = 2.5 degrees Celsius

a ( iron ) = 1.13 x \(10^{-5}\) \(K^{-1}\)

———————————————————————————————————————

l = l x a ( t2 - t1 )

t2 = t1 + \(\frac{l}{l*a}\)

Enter the data:

T2 = 2.5 + \(\frac{0.5}{1000*1.13*10^{-5} }\) = 46.75 degree Celsius

Thus the answer to your problem is, 46.75 degree Celsius

We want to see which statements describe the siutuations where "constant-acceleration motion" fails.

We will see that the correct option is the first one.

"In practice, no object's motion is actually very close to the constant acceleration model."

We need to analyze each statement.

1) In practice, no object's motion is actually very close to the constant acceleration model.

This is true, for example, if we return to the leaf example, we usually would say something that "a falling object is only affected due to gravitational acceleration" and we assume that the acceleration is constant, but this is actually false, as there are a lot of other forces like friction or air resistance that also contribute. These forces also depend on the shape of the falling object and the velocity at which it falls, so the contributions to the acceleration are not constants, thus the acceleration is not constant.

2) the conditions required for the constant-acceleration model are not present, then the model  may not describe the motion very well.

The conditions are not stated and depend on the particular situation, so this does not fit really well.

3) Any difference between the observed motion and the motion predicted by the constant- acceleration model must be the result of measurement error.

This is false, while yes, obviously, if you have a measurement error the predictions will be wrong, but even in the case where your measures are flawless, the constant-acceleration model ignores some things that contribute to the motion (are kinda small contributions, this is why we ignore them) so a lot of differences will be due to these contributions that we are ignoring.

So the correct statement is the first one.

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Answer:

The strengths become greater, as the number of turn increases,