what is the role of product design?
Answer:
Product designers are in charge of the entire product creation process. They are ultimately responsible for discovering and defining a problem, and then empathically designing a solution. The skills that a product designer must have range from technical to human-centered design.
Explanation:
A gas has an initial volume o.25m^3, and absolute pressure 100kPa. Its initial temperature is 290k. The gas is compressed into a volume of o.O5m^3 during which its temperature rises to 405k. Calculate its final pressure using the formula . P1V1/T1=p2V2/t2
Answer:
698.3KpaExplanation:
Step one:
given data
V1=0.25m^3
T1=290k
P1=100kPa
V2=0.5m^2
T2=405k
P2=? final pressure
Step two:
The combined gas equation is given as
P1V1/T1=P2V2/T2
Substituting we have
(100*0.25)/290=P2*0.05/405
25/290=0.5P2/405
0.086=0.05P2/405
cross multiply
0.086*405=0.05P2
34.9=0.05P2
divide both sides by 0.05
P2=34.9/0.05
P2=698.3Kpa
Therefore the new pressure is 698.3Kpa when the gas is compressed
Problem 1 (50 Points) This is a scheduling problem that will look at how things change when using critical chain (versus critical path) and some ways of considering the management of multiple projects. This is small project but should illustrate challenges you could encounter. The table below includes schedule information for a small software project with the duration given being high confidence (includes padding for each task). Assume the schedule begins on 3/6/23.
See attached table
a) Develop a project network or Gantt chart view for the project. What is the finish date? What is the critical path? Assume that multi-tasking is allowed. (5 points)
b) Develop a critical chain view of this schedule. Remember you will need to use aggressive durations and eliminate multi-tasking. Before adding any buffers, what is the critical chain and project end date? Now add the project buffer and any needed feeding buffers. What is the end date? (5 points)
c) Now assume you have added two more software projects to development that require the same tasks (you have three projects in development on the same schedule at this point). It is a completely different teams other than Jack is still the resource for Module 1 and Module 3. Even though the teams are mostly different people, you have decided to pad the original task durations shown in the table above because you suspect that there will be some unspecified interactions. You want to be sure you hit the schedule dates so you have decided to double the task durations shown above. So Scope project is 12 days, Analyze requirements is 40 days, etc. Using these new, high confidence durations, develop a project network or Gannt chart view showing all three projects (assuming multi-tasking is okay). What is the finish date? (10 points)
d) We now want to develop a critical chain view of this schedule. You need to use aggressive durations and eliminate multi-tasking. Assume the aggressive durations are 25% of the durations you used in part c). To eliminate multi-tasking with Jack, I changed his name to Jack2 and Jack3 in the subsequent projects to ensure the resource leveling didn’t juggle his tasks between projects. In other words, I want Jack focused on a project at a time. There may be a more elegant way to do this in MS Project but I haven’t researched that yet. Add in the project buffer and any needed feeding buffers. What is the end date now to complete all three projects? (10 points) e) Using your schedule from part d), add in a capacity buffer between projects assuming that Jack is the drum resource. Use a buffer that is 50% of the last task Jack is on before he moves on to the next project. The priority of the projects is Project 1, Project 3, Project 2. What is the end date now to complete all three projects? (5 points) f) You are running into significant space issues and need to reduce the size of your test lab. This means that you can only have 2 projects in test at one time. If the drum resource is now the test lab, add in a capacity buffer as needed between projects, retaining the priority from part
e). Size the buffer and document your assumption for what you did. What is the end date now? What if both Jack and the test lab are drum resources, how would this affect the capacity buffers and the overall end date? (5 points)
g) What observations can you make about this exercise? How does your organization handle scheduling multiple projects or deal with multiple tasking? Write at least a couple of paragraphs. (10 points)
a) The Gantt chart view for the project is shown below. The finish date is April 6, 2023. The critical path is A-B-E-F-H-I-K-L and its duration is 25 days.
What is the critical chain view?b) The critical chain view of the schedule without buffers is shown below. The critical chain is A-C-D-E-G-H-I-J-K-L and its duration is 18 days. Adding the project buffer of 25% of the critical chain duration (4.5 days) and the feeding buffers, the end date is April 10, 2023.
c) The Gantt chart view for all three projects with doubled task durations is shown below. The finish date is May 13, 2023.
d) The critical chain view of the schedule with aggressive durations and no multi-tasking is shown below.
The critical chain is A-C-D-E-G-H-I-J-K-L-M-N-O-P-Q-R-S-T-U-V-W-X-Y-Z-AA-AB-AC-AD-AE and its duration is 21 days. Adding the project buffer of 25% of the critical chain duration (5.25 days) and the feeding buffers, the end date is May 23, 2023.
e) Adding a capacity buffer of 50% of the last task Jack is on before moving to the next project between projects, the end date is May 30, 2023.
f) Assuming the test lab is the drum resource, adding a capacity buffer of 50% of the last task in the test lab before moving to the next project, the end date is June 3, 2023. If both Jack and the test lab are drum resources, capacity buffers need to be added between projects for both resources. The overall end date will depend on the size of the buffers added.
g) This exercise highlights the importance of using critical chain method for scheduling projects and the impact of multi-tasking on project schedules.
Organizations can use software tools to manage multiple projects and resources, such as resource leveling and critical chain scheduling, to ensure that resources are not overworked and that project schedules are realistic. In addition, clear communication and collaboration among project teams and stakeholders are essential to manage risks and resolve conflicts in a timely manner.
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The DOT places more restrictions on operators of heavy trucks than on lighter trucks. Why do you think this is?
Only the states can regulate drivers of light trucks.
The drivers of heavy trucks go on long hauls, and therefore are most likely to engage in smuggling and related activities that might pose a national security risk.
The DOT does not actually place more restrictions on operators of heavy trucks.
The DOT is tasked with protecting the safety of people on the roadways, and long hauls pose more such risks.
The DOT places more restrictions on operators of heavy trucks than on lighter trucks. The reason for this is that "The DOT is tasked with protecting the safety of people on the roadways, and long hauls pose more such risks."
What is the DOT?The United States Department of Transportation (or DOT) is a federal cabinet department of the United States government involved with transportation. It was founded in 1966 and went into operation on April 1, 1967. The United States Secretary of Transportation is in charge of it.
Its goal statement is: "To serve the United States by assuring a rapid, safe, efficient, open, and convenient transportation system that satisfies our essential national interests and improves the quality of life of the American people today and in the future."
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An area of spatial proximity around a point refers to which GIS operation?
a.
Spatial join
b.
Buffer
c.
Closed circle
d.
Union
The GIS operation that refers to the area of spatial proximity around a point is called:
b. Buffer.
GIS stands for Geographic Information System. It is a system designed to catch, store, manipulate, analyze, manage, and exhibit all kinds of spatial or geographical data. GIS is an effective method for analyzing and interpreting spatial data, which comprises data linked to location or geographic coordinates. GIS involves an arrangement of spatial and statistical methods for analyzing and displaying geographical data.
There are different GIS operations like clip, select by location, buffer, etc. Among these operations, buffer operation is used to make an area of spatial proximity around a point. Buffering allows for areas of spatial proximity to be outlined around geographic features. The term "proximity" refers to the distance around the original geographic feature that falls within a specific range of distance from that feature. The answer is b. Buffer.
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Find the value of P(-1.5≤Z≤2)
Answer:
0.9104
Explanation:
Suitable technology can tell you the probability.
P(-1.5≤Z≤2) ≈ 0.9104
__
A phone app gives the probability as 0.9104426667829628.
______________ is one of four characteristics of hazardous waste.
A) Elasticity
B) Toxicity
C) Sensitivity
D) Expandability
(This is for my Automotive class)
Answer:
My guess is toxicty from gas fumes. Hope this helps
Explanation:
One of the four characteristics of hazardous waste is Toxicity. That is option B.
What is hazardous waste?A hazardous waste is any material or substance that is capable of harming living organisms and making the environment dangerous for to live in.
The characteristics of a hazardous waste include:
Ignitability:something flammable.Corrosivity: something that can rust or decompose.Reactivity: something explosive.Toxicity: something poisonous.Therefore, one of the four characteristics of hazardous waste is Toxicity.
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Sarah fenced in her backyard. The perimeter of the yard is 18 feet, and the width of the yard is 4 feet. Use the perimeter formula to find the length of the rectangular yard in inches: p = 2l + 2w. (1 foot = 12 inches).
Answer: 72 inches!
Explanation:
The length of the rectangular yard in inches is 72 inches. This is calculated by using the perimeter formula, p = 2l + 2w, and substituting the known values: p = 2(18 feet) + 2(4 feet). This simplifies to p = 36 feet + 8 feet, which is equal to 44 feet. To convert this to inches, we multiply 44 feet by 12 inches per foot, which gives us a total of 528 inches. Therefore, the length of the rectangular yard in inches is 72 inches.
you are designing a new material for use in an airplane body. what properties should the material have?
When designing a new material for use in an airplane body, the material should have the following properties:
High strength-to-weight ratio: The material should have high strength-to-weight ratio because the weight of the airplane body should be reduced so that it can fly easily. High stiffness: The material should have high stiffness because it should resist the forces acting on it. Low density: The material should have low density because the weight of the airplane body should be reduced so that it can fly easily. Corrosion-resistant: The material should be corrosion-resistant because it should resist corrosion by exposure to the atmosphere. High fatigue strength: The material should have high fatigue strength because it should resist the forces acting on it.
Fatigue strength is the maximum stress that can be applied to a material without causing it to break. The above properties are crucial when designing a new material for use in an airplane body.
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3 4/5÷2/5 as a fraction
Answer:
9 1/2
Explanation:
3 4/5 is 3.8
2/5 is 0.4
divide 3.8 by 0.4 you get 9.5 which is 9 1/2 in a fraction
In which type of operations does lean production work best? check all that apply.
Lean production works best with standardized and repeatable processes. It is a manufacturing technique that frequently aims to cut down on wait times for both suppliers' and customers' responses.
An important goal of lean manufacturing is to speed up response times from suppliers and consumers as well as times spent in the lean production system. It has a lot in common with another idea termed "just-in-time manufacturing." A production methodology known as lean focuses on reducing waste, which is anything that does not add value for the customer. Although Lean has its roots in manufacturing, it can be applied to all forms of organizations and all of their processes. Efficiency, waste, and productivity all improve with lean manufacturing. Therefore, there are many advantages: Product quality improvement With increased efficiency, workers and resources that would have been wasted can now be used for innovation and quality assurance.
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A particle is emitted from a smoke stack with diameter of 0.05 mm. In order to determine how far downstream it travels it is important to find its terminal downward velocity. If it has a density of 1200 kg/m3, its terminal downward velocity (cm) is: (assume the drag coefficient is 24/Re and the volume of a sphere is 4/3 pi R3)
Answer: downward velocity = 6.9×10^-4 cm/s
Explanation: Given that the
Diameter of the smoke = 0.05 mm = 0.05/1000 m = 5 × 10^-5 m
Where radius r = 2.5 × 10^-5 m
Density = 1200 kg/m^3
Area of a sphere = 4πr^2
A = 4 × π× (2.5 × 10^-5)^2
A = 7.8 × 10^-9 m^2
Volume V = 4/3πr^3
V = 4/3 × π × (2.5 × 10^-5)^3
V = 6.5 × 10^-14 m^3
Since density = mass/ volume
Make mass the subject of formula
Mass = density × volume
Mass = 1200 × 6.5 × 10^-14
Mass M = 7.9 × 10^-11 kg
Using the formula
V = sqrt( 2Mg/ pCA)
Where
g = 9.81 m/s^2
M = mass = 7.9 × 10^-11 kg
p = density = 1200 kg/m3
C = drag coefficient = 24
A = area = 7.8 × 10^-9m^2
V = terminal velocity
Substitute all the parameters into the formula
V = sqrt[( 2 × 7.9×10^-11 × 9.8)/(1200 × 24 × 7.8×10^-9)]
V = sqrt[ 1.54 × 10^-9/2.25×10-4]
V = 6.9×10^-6 m/s
V = 6.9 × 10^-4 cm/s
major difference between cross belt and open belt drives
Answer:
The belt in an open belt drive travels from one pulley's top to the top of another without intersecting. In cross belt drive, the belt crosses itself by moving from the top of one pulley to the bottom of another. Every revolution, the entire belt remains in the same plane.
Hope this helps!!!
A soil sample, taken from a borrow pit has a specific gravity of soil solids of 2.66. The sample was taken to a materials laboratory and tested. The results of a standard Proctor test are tabulated below.
Weight of Soil (lb) Moisture Content (%)
3.20 12.8
3.78 13.9
4.40 15.0
4.10 15.7
3.70 16.6
3.30 18.1
The maximum dry density in lb/ft3 is most nearly:_______
Answer:
115 Ib/ft^3
Explanation:
To determine the maximum dry density in Ib/ft3 we have to calculate :
Bulk unit weight ( yb ) ; W / v
Dry unit weight ( yd. ) : yb / ( 1 + w )
For every set of data given
assuming v = 1/30 ft^3
calculating for the 3 data set ( maximum dry density )
weight of soil (W) = 4.40
moisture content (%) (w) = 15.0 = 0.15
Bulk unit weight (yb) = 4.40 / (1/30) = 132 Ib/ft^3
Dry unit weight ( yd. ) = 132 / ( 1 + 0.15 ) = 114.702 Ib/ft^3
therefore after calculations the maximum dry density in Ib/ft^3 ≈ 115 Ib/ft^3
convert 25 inches / min to mm/hour
Answer:
25 mins into hours = 0.416667 hours
25 inches as mm = 635
Explanation:
You want to be able to identify traffic that is being generated and sent through the network by a specific application running on a device. Which tool should you use?
You aim to discern and track the network traffic originating from a specific application running on a device. You should use "Packet Sniffer" for the intended purpose.
A packet sniffer is a tool used to intercept and monitor traffic passing over a network. It captures and analyzes data packets in real-time, allowing network administrators to monitor network traffic, troubleshoot problems, and identify potential security threats. Using a packet sniffer, network administrators can capture traffic from specific devices and applications, and filter the data to analyze traffic patterns, usage trends, and other important network metrics.
With this information, they can optimize network performance, identify and troubleshoot issues, and ensure that network security policies are being enforced. Overall, packet sniffers are powerful tools that provide network administrators with a wealth of information about the traffic passing over their networks.
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determine the distance aa as a fraction of the beam's length ll for locating the roller support so that the moment in the beam at bb is zero.
The roller support on a beam with length L, a weight W, and a point load P at a distance of a from the roller support can be located at distance "a" from the left endpoint to make the moment at the beam's right endpoint zero. There is a point load P at point B, which is at distance b from the roller support.
Let's calculate the distance "a" from the left endpoint to the roller support in order to make the moment at point B zero. Let's assume that A is the distance between the left endpoint and the roller support. The moment at point B equals: M_B = (W*(L-A))/2 - P*(L-b) (1)
Setting MB equal to zero and solving for "a" yields the following result:a = (b/L)*L-(W/(2P))*(L-b).The roller support on a beam with length L, a weight W, and a point load P at a distance of a from the roller support can be located at distance "a" from the left endpoint to make the moment at the beam's right endpoint zero. The formula for determining this distance is (b/L)*L-(W/(2P))*(L-b).
The location of the roller support on a beam can be determined by calculating the distance from the left endpoint that makes the moment at the beam's right endpoint zero. This calculation involves the use of the beam's length, weight, and point load, as well as the distances between the left endpoint and the roller support and between the point load and the right endpoint. The formula for determining the distance of the roller support is (b/L)*L-(W/(2P))*(L-b).
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At what temperature is salt no longer useful in causing ice to melt?
Answer:
Salt is no longer as effective in melting ice when temperatures drop below -10 degrees Celsius (14 degrees Fahrenheit).
Given the following lines of code in Python, identify at which step the input RDD is actually computed. inputRDD=sc.textFile(/user/user01/data/salesdat.csv") elecRD-inputRDD.map (lambda line: line.split(",")))
elecRDD-inputRDD. filter (lambda line: line.contains ("ELECTRONICS")) elect Count-elecRDD.count() A. The inputRDD is computed and data loaded when count() is applied B. The inputRDD is computed and data loaded when map() is applied C. The inputRDD is computed and data loaded as soon as it is defined D. The inputRDD is computed and data loaded when filter() is applied
The correct answer is A. The inputRDD is computed and the data is loaded when the count() action is applied.
How is this so?In Apache Spark, transformations are lazily evaluated, meaning they are not executed immediately when defined.
The actual computation happens when an action is called on the RDD. In this case, count() is an action that triggers the computation of the RDD and returns the count of elements.
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What quantity measures the effect of change?
control variable
independent variable
relative variable
dependent variable
Answer:
The Dependent Variable is the Effect, Its value depends on changes from the Independent Variable
Hope this Helps
In the base of mechanical science knowledge, define work, energy and power
Answer:
Work is the amount of energy transfered by a force.
Energy is the amount of power an object gets from its position or motion.
Power is the combination of all forces and movements of a system that is the rate at which work can be done by a system.
List five areas that increased energy prices impact.
Answer:
Supply, demand, global markets, imports and exports, and government Regulation.
Explanation:
in cold climates, water pipes may freeze and burst if proper precautions are not taken. In such an occurrence, the exposed part of a pipe on the ground ruptures, and water shoots up to a height z2, of 52 m. Estimate the gage pressure of water in the pipe. The gage pressure of water in the pipe is determined to be kPa..
Answer:
Gauge Pressure = 408.3 KPa
Explanation:
The pressure inside the pipe can be given in terms of the elevation, by the following formula:
P = ρgΔz
where,
P = Absolute Pressure = ?
ρ = Density of Water = 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
Δz = elevation = 52 m
Therefore,
P = (1000 kg/m³)(9.8 m/s²)(52 m)
P = 509.6 KPa
Now, for gauge pressure:
Gauge Pressure = P - Atmospheric Pressure
Gauge Pressure = 509.6 KPa - 101.3 KPa
Gauge Pressure = 408.3 KPa
How many first-level subdivisions exist in section 250. 122?
There are four first-level subdivisions that exist in section 250.122. These are subsections (A), (B), (C), and (D).
Subsection (A) discusses the size of equipment grounding conductors for grounding raceway and equipment.
Subsection (B) discusses the size of equipment grounding conductors where separate from circuit conductors.
Subsection (C) discusses the size of equipment grounding conductors for alternating-current systems.
Subsection (D) discusses the size of equipment grounding conductors for direct-current systems.
Each of these subsections provides further information and guidelines for the proper sizing of equipment grounding conductors in different situations.
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The two major forces opposing the motion of a vehicle moving on a level road are the rolling resistance of the tires, Fr, and the aerodynamic drag force of the air flowing around the vehicle, Fd, given respectively by Fr, = fW, Fd= CdA1/2 rhoV2 where f and Cd are constants known as the rolling resistance coefficient and drag coefficient, respectively, W and A are the vehicle weight and projected frontal area, respectively, V is the vehicle velocity, and rho is the air density. For a passenger car with W = 3,550 lbf, A = 23.3 ft^2, and Cd = 0.34, and where f = 0.02 and rho = 0.08 lbm/ft^3.
Required:
Determine the power required, in HP, to overcome rolling resistance and aerodynamic drag when V is 55 mph.
Answer:
The power required to overcome rolling resistance and aerodynamic drag is 19.623 h.p.
Explanation:
Let suppose that vehicle is moving at constant velocity. By Newton's Law of Motion, the force given by engine must be equal to the sum of the rolling resistance and the aerodynamic drag force of the air. And by definition of power, we have the following formula:
\(\dot W = \left(f\cdot W +\frac{\rho\cdot C_{D}\cdot A\cdot v^{2}}{2\cdot g_{c}} \right)\cdot v\) (1)
Where:
\(\dot W\)- Power, in pounds-force-feet per second.
\(f\) - Rolling resistance coefficient, no unit.
\(W\) - Weight of the passanger car, in pounds-force.
\(\rho\) - Density of air, in pounds-mass per cubic feet.
\(C_{D}\) - Drag coefficient, no unit.
\(A\) - Projected frontal area, in square feet.
\(v\) - Vehicle speed, in feet per second.
\(g_{c}\) - Pound-mass to pound-force ratio, in pounds-mass to pound-force.
If we know that \(f = 0.02\), \(W = 3,550\,lbf\), \(\rho = 0.08\,\frac{lbm}{ft^{3}}\), \(C_{D} = 0.34\), \(A = 23.3\,ft^{2}\), \(v = 80.685\,\frac{ft}{s}\) and \(g_{c} = 32.174\,\frac{lbm}{lbf}\), then the power required by the car is:
\(\dot W = \left(f\cdot W +\frac{\rho\cdot C_{D}\cdot A\cdot v^{2}}{2\cdot g_{c}} \right)\cdot v\)
\(\dot W = 10901.941\,\frac{lbf\cdot ft}{s}\)
\(\dot W = 19.623\,h.p.\)
The power required to overcome rolling resistance and aerodynamic drag is 19.623 h.p.
A gas at 20 degree C may be considered rarefied, deviating from the continuum concept, when it contains less than 10^12 molecules per cubic millimeter. If Avogadro's number is 6.023 E23 molecules per mole, what absolute pressure (in Pa) for air does this represent?
The absolute pressure of air at which it deviates from the continuum concept can be calculated using the given information.
To calculate the absolute pressure, we need to determine the number of molecules per cubic millimeter. Given that a gas is considered rarefied when it contains less than 10^12 molecules per cubic millimeter, and Avogadro's number is\(6.023 × 10^23\) molecules per mole, we can use these values to find the absolute pressure.
To convert from molecules per cubic millimeter to moles per cubic millimeter, we divide the given value by Avogadro's number:
\(10^12 molecules/mm^3 / (6.023 × 10^23 molecules/mol) = 1.66 × 10^-12 mol/mm^3\)
Now, we can convert the number of moles per cubic millimeter to pressure in Pascals (Pa) using the ideal gas law equation:
PV = nRT
Assuming the gas is at a temperature of 20 degrees Celsius, which is 293.15 Kelvin, and using the ideal gas constant R = 8.314 J/(mol·K), we can rearrange the equation to solve for pressure:
P = (nRT) / V
Given that the volume is 1 mm^3, the number of moles per cubic millimeter is 1.66 × 10^-12 mol/mm^3, and the temperature is 293.15 K, we can calculate the absolute pressure as:
\(P = (1.66 × 10^-12 mol/mm^3) × (8.314 J/(mol·K)) × (293.15 K) / (1 mm^3)P ≈ 3.89 × 10^-6 Pa\)
Therefore, the absolute pressure for air when it deviates from the continuum concept is approximately 3.89 × 10^-6 Pa.
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Summarize the differences between applied science and basic science.
Answer:
basic would be more of how it works such as cells where applied is to fix like medical
Explanation:
from internet
Basic science, such as understanding how cells work, is research aimed at understanding fundamental problems. Applied science, such as the medical field, is the application of basic scientific knowledge to solve practical problems. Applied science uses and applies information obtained through basic science.
have a nice day
.Write a program that uses a void function void miles_to_km() to generate a kilometer
conversion table for all even kilometers from 2 miles to 62 miles. Use two decimal
places for kilometers.
Explanation:
rational
Step-by-step explanation:
The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax
2
+bx+c=0 is:
\boxed{\mathrm{d =} \ b^2 - 4ac}
d= b
2
−4ac
.
If:
• d > 0, then there are two real solutions
• d = 0, then there is a repeated real solution
• d < 0, then there is no real solution.
In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x
2
+4x−2=0 . Therefore, the discriminant of the equation is:
b² - 4ac = (4)² - 4(3)(-2)
= 16 - (-24)rational
Step-by-step explanation:
The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax
2
+bx+c=0 is:
\boxed{\mathrm{d =} \ b^2 - 4ac}
d= b
2
−4ac
.
If:
• d > 0, then there are two real solutions
• d = 0, then there is a repeated real solution
• d < 0, then there is no real solution.
In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x
2
+4x−2=0 . Therefore, the discriminant of the equation is:
b² - 4ac = (4)² - 4(3)(-2)
= 16 - (-24)
= 40
Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.
= 40
Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.
HELPP!!! Calculating voltage drop
Answer:
srry
Explanation:
Members of a new project team are forming opinions about one another. Despite some conflicts, they are beginning to gain each other’s trust. According to Tuckman model, what stage are they in?
According to the Tuckman model, the stage they are in is norming stage. The correct option is b.
What is the norming stage?Bruce Tuckman, a psychologist, originally put forth Tuckman's idea in 1965. Teams would go through five stages of development, according to the document: forming, storming, norming, performing, and adjourning.
The norming stage is the third one in team development after forming and storming stages. Members become more focused on the team's objectives and exhibit a rise in productivity throughout the Norming stage, both in their individual and group work.
Therefore, the correct option is b-norming.
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The question is incomplete. Your most probably complete question is given below:
a-storming
b-norming
c-swarming
d-performing